mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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187 lines
18 KiB
JSON
187 lines
18 KiB
JSON
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"title": "Maximum Segment Sum After Removals",
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"titleSlug": "maximum-segment-sum-after-removals",
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"content": "<p>You are given two <strong>0-indexed</strong> integer arrays <code>nums</code> and <code>removeQueries</code>, both of length <code>n</code>. For the <code>i<sup>th</sup></code> query, the element in <code>nums</code> at the index <code>removeQueries[i]</code> is removed, splitting <code>nums</code> into different segments.</p>\n\n<p>A <strong>segment</strong> is a contiguous sequence of <strong>positive</strong> integers in <code>nums</code>. A <strong>segment sum</strong> is the sum of every element in a segment.</p>\n\n<p>Return<em> an integer array </em><code>answer</code><em>, of length </em><code>n</code><em>, where </em><code>answer[i]</code><em> is the <strong>maximum</strong> segment sum after applying the </em><code>i<sup>th</sup></code> <em>removal.</em></p>\n\n<p><strong>Note:</strong> The same index will <strong>not</strong> be removed more than once.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,5,6,1], removeQueries = [0,3,2,4,1]\n<strong>Output:</strong> [14,7,2,2,0]\n<strong>Explanation:</strong> Using 0 to indicate a removed element, the answer is as follows:\nQuery 1: Remove the 0th element, nums becomes [0,2,5,6,1] and the maximum segment sum is 14 for segment [2,5,6,1].\nQuery 2: Remove the 3rd element, nums becomes [0,2,5,0,1] and the maximum segment sum is 7 for segment [2,5].\nQuery 3: Remove the 2nd element, nums becomes [0,2,0,0,1] and the maximum segment sum is 2 for segment [2]. \nQuery 4: Remove the 4th element, nums becomes [0,2,0,0,0] and the maximum segment sum is 2 for segment [2]. \nQuery 5: Remove the 1st element, nums becomes [0,0,0,0,0] and the maximum segment sum is 0, since there are no segments.\nFinally, we return [14,7,2,2,0].</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,2,11,1], removeQueries = [3,2,1,0]\n<strong>Output:</strong> [16,5,3,0]\n<strong>Explanation:</strong> Using 0 to indicate a removed element, the answer is as follows:\nQuery 1: Remove the 3rd element, nums becomes [3,2,11,0] and the maximum segment sum is 16 for segment [3,2,11].\nQuery 2: Remove the 2nd element, nums becomes [3,2,0,0] and the maximum segment sum is 5 for segment [3,2].\nQuery 3: Remove the 1st element, nums becomes [3,0,0,0] and the maximum segment sum is 3 for segment [3].\nQuery 4: Remove the 0th element, nums becomes [0,0,0,0] and the maximum segment sum is 0, since there are no segments.\nFinally, we return [16,5,3,0].\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == nums.length == removeQueries.length</code></li>\n\t<li><code>1 <= n <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= nums[i] <= 10<sup>9</sup></code></li>\n\t<li><code>0 <= removeQueries[i] < n</code></li>\n\t<li>All the values of <code>removeQueries</code> are <strong>unique</strong>.</li>\n</ul>\n",
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"exampleTestcases": "[1,2,5,6,1]\n[0,3,2,4,1]\n[3,2,11,1]\n[3,2,1,0]",
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"code": "# @param {Integer[]} nums\n# @param {Integer[]} remove_queries\n# @return {Integer[]}\ndef maximum_segment_sum(nums, remove_queries)\n \nend",
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"hints": [
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"Use a sorted data structure to collect removal points and store the segments.",
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"Use a heap or priority queue to store segment sums and their corresponding boundaries.",
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"Make sure to remove invalid segments from the heap."
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