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leetcode-problemset/leetcode-cn/problem (Chinese)/算术三元组的数目 [number-of-arithmetic-triplets].html

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<p>给你一个下标从 <strong>0</strong> 开始、<strong>严格递增</strong> 的整数数组 <code>nums</code> 和一个正整数 <code>diff</code> 。如果满足下述全部条件,则三元组 <code>(i, j, k)</code> 就是一个 <strong>算术三元组</strong> </p>
<ul>
<li><code>i &lt; j &lt; k</code> </li>
<li><code>nums[j] - nums[i] == diff</code></li>
<li><code>nums[k] - nums[j] == diff</code></li>
</ul>
<p>返回不同 <strong>算术三元组</strong> 的数目<em></em></p>
<p>&nbsp;</p>
<p><strong>示例 1</strong></p>
<pre><strong>输入:</strong>nums = [0,1,4,6,7,10], diff = 3
<strong>输出:</strong>2
<strong>解释:</strong>
(1, 2, 4) 是算术三元组7 - 4 == 3 且 4 - 1 == 3 。
(2, 4, 5) 是算术三元组10 - 7 == 3 且 7 - 4 == 3 。
</pre>
<p><strong>示例 2</strong></p>
<pre><strong>输入:</strong>nums = [4,5,6,7,8,9], diff = 2
<strong>输出:</strong>2
<strong>解释:</strong>
(0, 2, 4) 是算术三元组8 - 6 == 2 且 6 - 4 == 2 。
(1, 3, 5) 是算术三元组9 - 7 == 2 且 7 - 5 == 2 。
</pre>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ul>
<li><code>3 &lt;= nums.length &lt;= 200</code></li>
<li><code>0 &lt;= nums[i] &lt;= 200</code></li>
<li><code>1 &lt;= diff &lt;= 50</code></li>
<li><code>nums</code> <strong>严格</strong> 递增</li>
</ul>