leetcode-problemset/leetcode-cn/problem (English)/最好的扑克手牌(English) [best-poker-hand].html

<p>You are given an integer array <code>ranks</code> and a character array <code>suits</code>. You have <code>5</code> cards where the <code>i<sup>th</sup></code> card has a rank of <code>ranks[i]</code> and a suit of <code>suits[i]</code>.</p>

<p>The following are the types of <strong>poker hands</strong> you can make from best to worst:</p>

<ol>
	<li><code>&quot;Flush&quot;</code>: Five cards of the same suit.</li>
	<li><code>&quot;Three of a Kind&quot;</code>: Three cards of the same rank.</li>
	<li><code>&quot;Pair&quot;</code>: Two cards of the same rank.</li>
	<li><code>&quot;High Card&quot;</code>: Any single card.</li>
</ol>

<p>Return <em>a string representing the <strong>best</strong> type of <strong>poker hand</strong> you can make with the given cards.</em></p>

<p><strong>Note</strong> that the return values are <strong>case-sensitive</strong>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> ranks = [13,2,3,1,9], suits = [&quot;a&quot;,&quot;a&quot;,&quot;a&quot;,&quot;a&quot;,&quot;a&quot;]
<strong>Output:</strong> &quot;Flush&quot;
<strong>Explanation:</strong> The hand with all the cards consists of 5 cards with the same suit, so we have a &quot;Flush&quot;.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> ranks = [4,4,2,4,4], suits = [&quot;d&quot;,&quot;a&quot;,&quot;a&quot;,&quot;b&quot;,&quot;c&quot;]
<strong>Output:</strong> &quot;Three of a Kind&quot;
<strong>Explanation:</strong> The hand with the first, second, and fourth card consists of 3 cards with the same rank, so we have a &quot;Three of a Kind&quot;.
Note that we could also make a &quot;Pair&quot; hand but &quot;Three of a Kind&quot; is a better hand.
Also note that other cards could be used to make the &quot;Three of a Kind&quot; hand.</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> ranks = [10,10,2,12,9], suits = [&quot;a&quot;,&quot;b&quot;,&quot;c&quot;,&quot;a&quot;,&quot;d&quot;]
<strong>Output:</strong> &quot;Pair&quot;
<strong>Explanation:</strong> The hand with the first and second card consists of 2 cards with the same rank, so we have a &quot;Pair&quot;.
Note that we cannot make a &quot;Flush&quot; or a &quot;Three of a Kind&quot;.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>ranks.length == suits.length == 5</code></li>
	<li><code>1 &lt;= ranks[i] &lt;= 13</code></li>
	<li><code>&#39;a&#39; &lt;= suits[i] &lt;= &#39;d&#39;</code></li>
	<li>No two cards have the same rank and suit.</li>
</ul>