2022-03-27 20:52:13 +08:00
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<p>Given the <code>root</code> of a binary tree, return the leftmost value in the last row of the tree.</p>
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<p> </p>
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2023-12-09 18:42:21 +08:00
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<p><strong class="example">Example 1:</strong></p>
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2022-03-27 20:52:13 +08:00
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<img alt="" src="https://assets.leetcode.com/uploads/2020/12/14/tree1.jpg" style="width: 302px; height: 182px;" />
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<pre>
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<strong>Input:</strong> root = [2,1,3]
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<strong>Output:</strong> 1
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</pre>
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2023-12-09 18:42:21 +08:00
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<p><strong class="example">Example 2:</strong></p>
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2022-03-27 20:52:13 +08:00
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<img alt="" src="https://assets.leetcode.com/uploads/2020/12/14/tree2.jpg" style="width: 432px; height: 421px;" />
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<pre>
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<strong>Input:</strong> root = [1,2,3,4,null,5,6,null,null,7]
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<strong>Output:</strong> 7
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</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li>The number of nodes in the tree is in the range <code>[1, 10<sup>4</sup>]</code>.</li>
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<li><code>-2<sup>31</sup> <= Node.val <= 2<sup>31</sup> - 1</code></li>
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</ul>
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