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{
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"title": "Account Balance After Rounded Purchase",
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"content": "<p>Initially, you have a bank account balance of <code>100</code> dollars.</p>\n\n<p>You are given an integer <code>purchaseAmount</code> representing the amount you will spend on a purchase in dollars.</p>\n\n<p>At the store where you will make the purchase, the purchase amount is rounded to the <strong>nearest multiple</strong> of <code>10</code>. In other words, you pay a <strong>non-negative</strong> amount, <code>roundedAmount</code>, such that <code>roundedAmount</code> is a multiple of <code>10</code> and <code>abs(roundedAmount - purchaseAmount)</code> is <strong>minimized</strong>.</p>\n\n<p>If there is more than one nearest multiple of <code>10</code>, the <strong>largest multiple</strong> is chosen.</p>\n\n<p>Return <em>an integer denoting your account balance after making a purchase worth </em><code>purchaseAmount</code><em> dollars from the store.</em></p>\n\n<p><strong>Note:</strong> <code>0</code> is considered to be a multiple of <code>10</code> in this problem.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> purchaseAmount = 9\n<strong>Output:</strong> 90\n<strong>Explanation:</strong> In this example, the nearest multiple of 10 to 9 is 10. Hence, your account balance becomes 100 - 10 = 90.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> purchaseAmount = 15\n<strong>Output:</strong> 80\n<strong>Explanation:</strong> In this example, there are two nearest multiples of 10 to 15: 10 and 20. So, the larger multiple, 20, is chosen.\nHence, your account balance becomes 100 - 20 = 80.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= purchaseAmount &lt;= 100</code></li>\n</ul>\n",
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"code": "class Solution(object):\n def accountBalanceAfterPurchase(self, purchaseAmount):\n \"\"\"\n :type purchaseAmount: int\n :rtype: int\n \"\"\"\n ",
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"code": "/**\n * @param {number} purchaseAmount\n * @return {number}\n */\nvar accountBalanceAfterPurchase = function(purchaseAmount) {\n \n};",
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"code": "class Solution {\n\n /**\n * @param Integer $purchaseAmount\n * @return Integer\n */\n function accountBalanceAfterPurchase($purchaseAmount) {\n \n }\n}",
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"lang": "Kotlin",
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"lang": "Go",
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"lang": "Ruby",
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"code": "# @param {Integer} purchase_amount\n# @return {Integer}\ndef account_balance_after_purchase(purchase_amount)\n \nend",
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"lang": "Erlang",
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"code": "-spec account_balance_after_purchase(PurchaseAmount :: integer()) -> integer().\naccount_balance_after_purchase(PurchaseAmount) ->\n .",
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"code": "defmodule Solution do\n @spec account_balance_after_purchase(purchase_amount :: integer) :: integer\n def account_balance_after_purchase(purchase_amount) do\n\n end\nend",
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"hints": [
"To determine the nearest multiple of 10, we can brute force the rounded amount since there are at most 100 options. In case of multiple nearest multiples, choose the largest.",
"Another solution is observing that the rounded amount is floor((purchaseAmount + 5) / 10) * 10. Using this formula, we can calculate the account balance without having to brute force the rounded amount."
],
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