leetcode-problemset/leetcode-cn/originData/[no content]check-if-there-is-a-path-with-equal-number-of-0s-and-1s.json

{
    "data": {
        "question": {
            "questionId": "2653",
            "questionFrontendId": "2510",
            "categoryTitle": "Algorithms",
            "boundTopicId": 2028770,
            "title": "Check if There is a Path With Equal Number of 0's And 1's",
            "titleSlug": "check-if-there-is-a-path-with-equal-number-of-0s-and-1s",
            "content": null,
            "translatedTitle": "检查是否有路径经过相同数量的 0 和 1",
            "translatedContent": null,
            "isPaidOnly": true,
            "difficulty": "Medium",
            "likes": 1,
            "dislikes": 0,
            "isLiked": null,
            "similarQuestions": "[]",
            "contributors": [],
            "langToValidPlayground": null,
            "topicTags": [
                {
                    "name": "Array",
                    "slug": "array",
                    "translatedName": "数组",
                    "__typename": "TopicTagNode"
                },
                {
                    "name": "Dynamic Programming",
                    "slug": "dynamic-programming",
                    "translatedName": "动态规划",
                    "__typename": "TopicTagNode"
                },
                {
                    "name": "Matrix",
                    "slug": "matrix",
                    "translatedName": "矩阵",
                    "__typename": "TopicTagNode"
                }
            ],
            "companyTagStats": null,
            "codeSnippets": null,
            "stats": "{\"totalAccepted\": \"304\", \"totalSubmission\": \"456\", \"totalAcceptedRaw\": 304, \"totalSubmissionRaw\": 456, \"acRate\": \"66.7%\"}",
            "hints": [
                "Can you use dynamic programming to solve the problem?",
                "Let dp[i][j][diff] be true if there is a path from the cell (i, j) to (m - 1, n - 1) such that the difference between the number of 0’s and the number of 1’s that we visited so far is diff, or false otherwise. The answer to the problem will be dp[0][0][0]. How do you compute this dp?"
            ],
            "solution": null,
            "status": null,
            "sampleTestCase": "[[0,1,0,0],[0,1,0,0],[1,0,1,0]]",
            "metaData": "{\n  \"name\": \"isThereAPath\",\n  \"params\": [\n    {\n      \"name\": \"grid\",\n      \"type\": \"integer[][]\"\n    }\n  ],\n  \"return\": {\n    \"type\": \"boolean\"\n  }\n}",
            "judgerAvailable": true,
            "judgeType": "large",
            "mysqlSchemas": [],
            "enableRunCode": true,
            "envInfo": "{\"cpp\":[\"C++\",\"<p>\\u7248\\u672c\\uff1a<code>clang 11<\\/code> \\u91c7\\u7528\\u6700\\u65b0C++ 20\\u6807\\u51c6\\u3002<\\/p>\\r\\n\\r\\n<p>\\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528<code>-O2<\\/code>\\u7ea7\\u4f18\\u5316\\u3002<a href=\\\"https:\\/\\/github.com\\/google\\/sanitizers\\/wiki\\/AddressSanitizer\\\" target=\\\"_blank\\\">AddressSanitizer<\\/a> \\u4e5f\\u88ab\\u5f00\\u542f\\u6765\\u68c0\\u6d4b<code>out-of-bounds<\\/code>\\u548c<code>use-after-free<\\/code>\\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\"],\"java\":[\"Java\",\"<p>\\u7248\\u672c\\uff1a<code>OpenJDK 17<\\/code>\\u3002\\u53ef\\u4ee5\\u4f7f\\u7528Java 8\\u7684\\u7279\\u6027\\u4f8b\\u5982\\uff0clambda expressions \\u548c stream API\\u3002<\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u88ab\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5305\\u542b Pair \\u7c7b: https:\\/\\/docs.oracle.com\\/javase\\/8\\/javafx\\/api\\/javafx\\/util\\/Pair.html <\\/p>\"],\"python\":[\"Python\",\"<p>\\u7248\\u672c\\uff1a <code>Python 2.7.12<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982\\uff1a<a href=\\\"https:\\/\\/docs.python.org\\/2\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/2\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/2\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u6ce8\\u610f Python 2.7 <a href=\\\"https:\\/\\/www.python.org\\/dev\\/peps\\/pep-0373\\/\\\" target=\\\"_blank\\\">\\u5c06\\u57282020\\u5e74\\u540e\\u4e0d\\u518d\\u7ef4\\u62a4<\\/a>\\u3002 \\u5982\\u60f3\\u4f7f\\u7528\\u6700\\u65b0\\u7248\\u7684Python\\uff0c\\u8bf7\\u9009\\u62e9Python 3\\u3002<\\/p>\"],\"c\":[\"C\",\"<p>\\u7248\\u672c\\uff1a<code>GCC 8.2<\\/code>\\uff0c\\u91c7\\u7528GNU11\\u6807\\u51c6\\u3002<\\/p>\\r\\n\\r\\n<p>\\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528<code>-O1<\\/code>\\u7ea7\\u4f18\\u5316\\u3002 <a href=\\\"https:\\/\\/github.com\\/google\\/sanitizers\\/wiki\\/AddressSanitizer\\\" target=\\\"_blank\\\">AddressSanitizer<\\/a>\\u4e5f\\u88ab\\u5f00\\u542f\\u6765\\u68c0\\u6d4b<code>out-of-bounds<\\/code>\\u548c<code>use-after-free<\\/code>\\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u60f3\\u4f7f\\u7528\\u54c8\\u5e0c\\u8868\\u8fd0\\u7b97, \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 <a href=\\\"https:\\/\\/troydhanson.github.io\\/uthash\\/\\\" target=\\\"_blank\\\">uthash<\\/a>\\u3002 \\\"uthash.h\\\"\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5bfc\\u5165\\u3002\\u8bf7\\u770b\\u5982\\u4e0b\\u793a\\u4f8b:<\\/p>\\r\\n\\r\\n<p><b>1. \\u5f80\\u54c8\\u5e0c\\u8868\\u4e2d\\u6dfb\\u52a0\\u4e00\\u4e2a\\u5bf9\\u8c61\\uff1a<\\/b>\\r\\n<pre>\\r\\nstruct hash_entry {\\r\\n    int id;            \\/* we'll use this field as the key *\\/\\r\\n    char name[10];\\r\\n    UT_hash_handle hh; \\/* makes this structure hashable *\\/\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry *s) {\\r\\n    HASH_ADD_INT(users, id, s);\\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\\r\\n\\r\\n<p><b>2. \\u5728\\u54c8\\u5e0c\\u8868\\u4e2d\\u67e5\\u627e\\u4e00\\u4e2a\\u5bf9\\u8c61\\uff1a<\\/b>\\r\\n<pre>\\r\\nstruct hash_entry *find_user(int user_id) {\\r\\n    struct hash_entry *s;\\r\\n    HASH_FIND_INT(users, &user_id, s);\\r\\n    re
            "book": null,
            "isSubscribed": false,
            "isDailyQuestion": false,
            "dailyRecordStatus": null,
            "editorType": "CKEDITOR",
            "ugcQuestionId": null,
            "style": "LEETCODE",
            "exampleTestcases": "[[0,1,0,0],[0,1,0,0],[1,0,1,0]]\n[[1,1,0],[0,0,1],[1,0,0]]",
            "__typename": "QuestionNode"
        }
    }
}