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"title": "Maximum Performance of a Team",
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"content": "<p>You are given two integers <code>n</code> and <code>k</code> and two integer arrays <code>speed</code> and <code>efficiency</code> both of length <code>n</code>. There are <code>n</code> engineers numbered from <code>1</code> to <code>n</code>. <code>speed[i]</code> and <code>efficiency[i]</code> represent the speed and efficiency of the <code>i<sup>th</sup></code> engineer respectively.</p>\n\n<p>Choose <strong>at most</strong> <code>k</code> different engineers out of the <code>n</code> engineers to form a team with the maximum <strong>performance</strong>.</p>\n\n<p>The performance of a team is the sum of their engineers&#39; speeds multiplied by the minimum efficiency among their engineers.</p>\n\n<p>Return <em>the maximum performance of this team</em>. Since the answer can be a huge number, return it <strong>modulo</strong> <code>10<sup>9</sup> + 7</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 2\n<strong>Output:</strong> 60\n<strong>Explanation:</strong> \nWe have the maximum performance of the team by selecting engineer 2 (with speed=10 and efficiency=4) and engineer 5 (with speed=5 and efficiency=7). That is, performance = (10 + 5) * min(4, 7) = 60.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 3\n<strong>Output:</strong> 68\n<strong>Explanation:\n</strong>This is the same example as the first but k = 3. We can select engineer 1, engineer 2 and engineer 5 to get the maximum performance of the team. That is, performance = (2 + 10 + 5) * min(5, 4, 7) = 68.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 4\n<strong>Output:</strong> 72\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= k &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>speed.length == n</code></li>\n\t<li><code>efficiency.length == n</code></li>\n\t<li><code>1 &lt;= speed[i] &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= efficiency[i] &lt;= 10<sup>8</sup></code></li>\n</ul>\n",
"translatedTitle": "最大的团队表现值",
"translatedContent": "<p>公司有编号为 <code>1</code>&nbsp;到 <code>n</code>&nbsp;的 <code>n</code>&nbsp;个工程师,给你两个数组 <code>speed</code>&nbsp;和 <code>efficiency</code>&nbsp;,其中 <code>speed[i]</code>&nbsp;和 <code>efficiency[i]</code>&nbsp;分别代表第 <code>i</code>&nbsp;位工程师的速度和效率。请你返回由最多&nbsp;<code>k</code>&nbsp;个工程师组成的&nbsp;<strong>​​​​​​最大团队表现值</strong>&nbsp;,由于答案可能很大,请你返回结果对 <code>10^9 + 7</code> 取余后的结果。</p>\n\n<p><strong>团队表现值</strong>&nbsp;的定义为:一个团队中「所有工程师速度的和」乘以他们「效率值中的最小值」。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre><strong>输入:</strong>n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 2\n<strong>输出:</strong>60\n<strong>解释:</strong>\n我们选择工程师 2speed=10 且 efficiency=4和工程师 5speed=5 且 efficiency=7。他们的团队表现值为 performance = (10 + 5) * min(4, 7) = 60 。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre><strong>输入:</strong>n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 3\n<strong>输出:</strong>68\n<strong>解释:\n</strong>此示例与第一个示例相同,除了 k = 3 。我们可以选择工程师 1 ,工程师 2 和工程师 5 得到最大的团队表现值。表现值为 performance = (2 + 10 + 5) * min(5, 4, 7) = 68 。\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre><strong>输入:</strong>n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 4\n<strong>输出:</strong>72\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10^5</code></li>\n\t<li><code>speed.length == n</code></li>\n\t<li><code>efficiency.length == n</code></li>\n\t<li><code>1 &lt;= speed[i] &lt;= 10^5</code></li>\n\t<li><code>1 &lt;= efficiency[i] &lt;= 10^8</code></li>\n\t<li><code>1 &lt;= k &lt;= n</code></li>\n</ul>\n",
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