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{
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"question": {
"questionId": "1000311",
"questionFrontendId": "剑指 Offer II 052",
"categoryTitle": "LCOF2",
"boundTopicId": 910305,
"title": "展平二叉搜索树",
"titleSlug": "NYBBNL",
"content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\n",
"translatedTitle": "展平二叉搜索树",
"translatedContent": "<p>给你一棵二叉搜索树,请&nbsp;<strong>按中序遍历</strong> 将其重新排列为一棵递增顺序搜索树,使树中最左边的节点成为树的根节点,并且每个节点没有左子节点,只有一个右子节点。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/11/17/ex1.jpg\" style=\"width: 600px; height: 350px;\" /></p>\n\n<pre>\n<strong>输入:</strong>root = [5,3,6,2,4,null,8,1,null,null,null,7,9]\n<strong>输出:</strong>[1,null,2,null,3,null,4,null,5,null,6,null,7,null,8,null,9]\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/11/17/ex2.jpg\" style=\"width: 300px; height: 114px;\" /></p>\n\n<pre>\n<strong>输入:</strong>root = [5,1,7]\n<strong>输出:</strong>[1,null,5,null,7]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>树中节点数的取值范围是 <code>[1, 100]</code></li>\n\t<li><code>0 &lt;= Node.val &lt;= 1000</code></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><meta charset=\"UTF-8\" />注意:本题与主站 897&nbsp;题相同:&nbsp;<a href=\"https://leetcode-cn.com/problems/increasing-order-search-tree/\">https://leetcode-cn.com/problems/increasing-order-search-tree/</a></p>\n",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * TreeNode *left;\n * TreeNode *right;\n * TreeNode() : val(0), left(nullptr), right(nullptr) {}\n * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n TreeNode* increasingBST(TreeNode* root) {\n\n }\n};",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * int val;\n * TreeNode left;\n * TreeNode right;\n * TreeNode() {}\n * TreeNode(int val) { this.val = val; }\n * TreeNode(int val, TreeNode left, TreeNode right) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\nclass Solution {\n public TreeNode increasingBST(TreeNode root) {\n\n }\n}",
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"lang": "Python",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution(object):\n def increasingBST(self, root):\n \"\"\"\n :type root: TreeNode\n :rtype: TreeNode\n \"\"\"",
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"code": "# Definition for a binary tree node.\n# class TreeNode:\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution:\n def increasingBST(self, root: TreeNode) -> TreeNode:",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * struct TreeNode *left;\n * struct TreeNode *right;\n * };\n */\n\n\nstruct TreeNode* increasingBST(struct TreeNode* root){\n\n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public TreeNode IncreasingBST(TreeNode root) {\n\n }\n}",
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"lang": "JavaScript",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @return {TreeNode}\n */\nvar increasingBST = function(root) {\n\n};",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func increasingBST(_ root: TreeNode?) -> TreeNode? {\n\n }\n}",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun increasingBST(root: TreeNode?): TreeNode? {\n\n }\n}",
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"lang": "Rust",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n//\n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn increasing_bst(root: Option<Rc<RefCell<TreeNode>>>) -> Option<Rc<RefCell<TreeNode>>> {\n\n }\n}",
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"lang": "PHP",
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