leetcode-problemset/leetcode-cn/originData/last-stone-weight.json

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            "questionId": "1127",
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            "categoryTitle": "Algorithms",
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            "title": "Last Stone Weight",
            "titleSlug": "last-stone-weight",
            "content": "<p>You are given an array of integers <code>stones</code> where <code>stones[i]</code> is the weight of the <code>i<sup>th</sup></code> stone.</p>\n\n<p>We are playing a game with the stones. On each turn, we choose the <strong>heaviest two stones</strong> and smash them together. Suppose the heaviest two stones have weights <code>x</code> and <code>y</code> with <code>x &lt;= y</code>. The result of this smash is:</p>\n\n<ul>\n\t<li>If <code>x == y</code>, both stones are destroyed, and</li>\n\t<li>If <code>x != y</code>, the stone of weight <code>x</code> is destroyed, and the stone of weight <code>y</code> has new weight <code>y - x</code>.</li>\n</ul>\n\n<p>At the end of the game, there is <strong>at most one</strong> stone left.</p>\n\n<p>Return <em>the weight of the last remaining stone</em>. If there are no stones left, return <code>0</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> stones = [2,7,4,1,8,1]\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> \nWe combine 7 and 8 to get 1 so the array converts to [2,4,1,1,1] then,\nwe combine 2 and 4 to get 2 so the array converts to [2,1,1,1] then,\nwe combine 2 and 1 to get 1 so the array converts to [1,1,1] then,\nwe combine 1 and 1 to get 0 so the array converts to [1] then that&#39;s the value of the last stone.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> stones = [1]\n<strong>Output:</strong> 1\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= stones.length &lt;= 30</code></li>\n\t<li><code>1 &lt;= stones[i] &lt;= 1000</code></li>\n</ul>\n",
            "translatedTitle": "最后一块石头的重量",
            "translatedContent": "<p>有一堆石头，每块石头的重量都是正整数。</p>\n\n<p>每一回合，从中选出两块<strong> 最重的</strong> 石头，然后将它们一起粉碎。假设石头的重量分别为 <code>x</code> 和 <code>y</code>，且 <code>x <= y</code>。那么粉碎的可能结果如下：</p>\n\n<ul>\n\t<li>如果 <code>x == y</code>，那么两块石头都会被完全粉碎；</li>\n\t<li>如果 <code>x != y</code>，那么重量为 <code>x</code> 的石头将会完全粉碎，而重量为 <code>y</code> 的石头新重量为 <code>y-x</code>。</li>\n</ul>\n\n<p>最后，最多只会剩下一块石头。返回此石头的重量。如果没有石头剩下，就返回 <code>0</code>。</p>\n\n<p> </p>\n\n<p><strong>示例：</strong></p>\n\n<pre>\n<strong>输入：</strong>[2,7,4,1,8,1]\n<strong>输出：</strong>1\n<strong>解释：</strong>\n先选出 7 和 8，得到 1，所以数组转换为 [2,4,1,1,1]，\n再选出 2 和 4，得到 2，所以数组转换为 [2,1,1,1]，\n接着是 2 和 1，得到 1，所以数组转换为 [1,1,1]，\n最后选出 1 和 1，得到 0，最终数组转换为 [1]，这就是最后剩下那块石头的重量。</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= stones.length <= 30</code></li>\n\t<li><code>1 <= stones[i] <= 1000</code></li>\n</ul>\n",
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