mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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175 lines
16 KiB
JSON
175 lines
16 KiB
JSON
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"title": "Minimum Number of Taps to Open to Water a Garden",
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"content": "<p>There is a one-dimensional garden on the x-axis. The garden starts at the point <code>0</code> and ends at the point <code>n</code>. (i.e The length of the garden is <code>n</code>).</p>\n\n<p>There are <code>n + 1</code> taps located at points <code>[0, 1, ..., n]</code> in the garden.</p>\n\n<p>Given an integer <code>n</code> and an integer array <code>ranges</code> of length <code>n + 1</code> where <code>ranges[i]</code> (0-indexed) means the <code>i-th</code> tap can water the area <code>[i - ranges[i], i + ranges[i]]</code> if it was open.</p>\n\n<p>Return <em>the minimum number of taps</em> that should be open to water the whole garden, If the garden cannot be watered return <strong>-1</strong>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/01/16/1685_example_1.png\" style=\"width: 525px; height: 255px;\" />\n<pre>\n<strong>Input:</strong> n = 5, ranges = [3,4,1,1,0,0]\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> The tap at point 0 can cover the interval [-3,3]\nThe tap at point 1 can cover the interval [-3,5]\nThe tap at point 2 can cover the interval [1,3]\nThe tap at point 3 can cover the interval [2,4]\nThe tap at point 4 can cover the interval [4,4]\nThe tap at point 5 can cover the interval [5,5]\nOpening Only the second tap will water the whole garden [0,5]\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 3, ranges = [0,0,0,0]\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> Even if you activate all the four taps you cannot water the whole garden.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= n <= 10<sup>4</sup></code></li>\n\t<li><code>ranges.length == n + 1</code></li>\n\t<li><code>0 <= ranges[i] <= 100</code></li>\n</ul>\n",
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"code": "class Solution(object):\n def minTaps(self, n, ranges):\n \"\"\"\n :type n: int\n :type ranges: List[int]\n :rtype: int\n \"\"\"\n ",
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"code": "/**\n * @param {number} n\n * @param {number[]} ranges\n * @return {number}\n */\nvar minTaps = function(n, ranges) {\n \n};",
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"code": "# @param {Integer} n\n# @param {Integer[]} ranges\n# @return {Integer}\ndef min_taps(n, ranges)\n \nend",
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"code": "class Solution {\n func minTaps(_ n: Int, _ ranges: [Int]) -> Int {\n \n }\n}",
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"code": "func minTaps(n int, ranges []int) int {\n \n}",
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"code": "object Solution {\n def minTaps(n: Int, ranges: Array[Int]): Int = {\n \n }\n}",
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"code": "class Solution {\n fun minTaps(n: Int, ranges: IntArray): Int {\n \n }\n}",
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"code": "impl Solution {\n pub fn min_taps(n: i32, ranges: Vec<i32>) -> i32 {\n \n }\n}",
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"code": "class Solution {\n\n /**\n * @param Integer $n\n * @param Integer[] $ranges\n * @return Integer\n */\n function minTaps($n, $ranges) {\n \n }\n}",
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"hints": [
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"Create intervals of the area covered by each tap, sort intervals by the left end.",
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"We need to cover the interval [0, n]. we can start with the first interval and out of all intervals that intersect with it we choose the one that covers the farthest point to the right.",
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"What if there is a gap between intervals that is not covered ? we should stop and return -1 as there is some interval that cannot be covered."
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