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30 lines
1.4 KiB
HTML
30 lines
1.4 KiB
HTML
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<p>Given an <code>n x n</code> array of integers <code>matrix</code>, return <em>the <strong>minimum sum</strong> of any <strong>falling path</strong> through</em> <code>matrix</code>.</p>
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<p>A <strong>falling path</strong> starts at any element in the first row and chooses the element in the next row that is either directly below or diagonally left/right. Specifically, the next element from position <code>(row, col)</code> will be <code>(row + 1, col - 1)</code>, <code>(row + 1, col)</code>, or <code>(row + 1, col + 1)</code>.</p>
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<p> </p>
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<p><strong>Example 1:</strong></p>
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<img alt="" src="https://assets.leetcode.com/uploads/2021/11/03/failing1-grid.jpg" style="width: 499px; height: 500px;" />
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<pre>
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<strong>Input:</strong> matrix = [[2,1,3],[6,5,4],[7,8,9]]
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<strong>Output:</strong> 13
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<strong>Explanation:</strong> There are two falling paths with a minimum sum as shown.
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</pre>
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<p><strong>Example 2:</strong></p>
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<img alt="" src="https://assets.leetcode.com/uploads/2021/11/03/failing2-grid.jpg" style="width: 164px; height: 365px;" />
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<pre>
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<strong>Input:</strong> matrix = [[-19,57],[-40,-5]]
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<strong>Output:</strong> -59
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<strong>Explanation:</strong> The falling path with a minimum sum is shown.
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</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code>n == matrix.length == matrix[i].length</code></li>
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<li><code>1 <= n <= 100</code></li>
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<li><code>-100 <= matrix[i][j] <= 100</code></li>
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</ul>
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