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<p>Given the <code>head</code> of a linked list, remove the <code>n<sup>th</sup></code> node from the end of the list and return its head.</p>
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<p> </p>
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2023-12-09 18:42:21 +08:00
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<p><strong class="example">Example 1:</strong></p>
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<img alt="" src="https://assets.leetcode.com/uploads/2020/10/03/remove_ex1.jpg" style="width: 542px; height: 222px;" />
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<pre>
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<strong>Input:</strong> head = [1,2,3,4,5], n = 2
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<strong>Output:</strong> [1,2,3,5]
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</pre>
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2023-12-09 18:42:21 +08:00
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<p><strong class="example">Example 2:</strong></p>
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2022-03-27 20:56:26 +08:00
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<pre>
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<strong>Input:</strong> head = [1], n = 1
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<strong>Output:</strong> []
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</pre>
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2023-12-09 18:42:21 +08:00
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<p><strong class="example">Example 3:</strong></p>
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2022-03-27 20:56:26 +08:00
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<pre>
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<strong>Input:</strong> head = [1,2], n = 1
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<strong>Output:</strong> [1]
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</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li>The number of nodes in the list is <code>sz</code>.</li>
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<li><code>1 <= sz <= 30</code></li>
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<li><code>0 <= Node.val <= 100</code></li>
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<li><code>1 <= n <= sz</code></li>
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</ul>
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<p> </p>
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<p><strong>Follow up:</strong> Could you do this in one pass?</p>
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