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leetcode-problemset/leetcode-cn/originData/actors-and-directors-who-cooperated-at-least-three-times.json

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{
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"question": {
"questionId": "1136",
"questionFrontendId": "1050",
"categoryTitle": "Database",
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"title": "Actors and Directors Who Cooperated At Least Three Times",
"titleSlug": "actors-and-directors-who-cooperated-at-least-three-times",
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"content": "<p>Table: <code>ActorDirector</code></p>\n\n<pre>\n+-------------+---------+\n| Column Name | Type |\n+-------------+---------+\n| actor_id | int |\n| director_id | int |\n| timestamp | int |\n+-------------+---------+\ntimestamp is the primary key (column with unique values) for this table.\n</pre>\n\n<p>&nbsp;</p>\n\n<p>Write a solution to find all the pairs <code>(actor_id, director_id)</code> where the actor has cooperated with the director at least three times.</p>\n\n<p>Return the result table in <strong>any order</strong>.</p>\n\n<p>The result format is in the following example.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> \nActorDirector table:\n+-------------+-------------+-------------+\n| actor_id | director_id | timestamp |\n+-------------+-------------+-------------+\n| 1 | 1 | 0 |\n| 1 | 1 | 1 |\n| 1 | 1 | 2 |\n| 1 | 2 | 3 |\n| 1 | 2 | 4 |\n| 2 | 1 | 5 |\n| 2 | 1 | 6 |\n+-------------+-------------+-------------+\n<strong>Output:</strong> \n+-------------+-------------+\n| actor_id | director_id |\n+-------------+-------------+\n| 1 | 1 |\n+-------------+-------------+\n<strong>Explanation:</strong> The only pair is (1, 1) where they cooperated exactly 3 times.\n</pre>\n",
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"translatedTitle": "合作过至少三次的演员和导演",
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"translatedContent": "<p><code>ActorDirector</code>&nbsp;表:</p>\n\n<pre>\n+-------------+---------+\n| Column Name | Type |\n+-------------+---------+\n| actor_id | int |\n| director_id | int |\n| timestamp | int |\n+-------------+---------+\ntimestamp 是这张表的主键(具有唯一值的列).\n</pre>\n\n<p>&nbsp;</p>\n\n<p>编写解决方案找出合作过至少三次的演员和导演的 id 对&nbsp;<code>(actor_id, director_id)</code></p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>\nActorDirector 表:\n+-------------+-------------+-------------+\n| actor_id | director_id | timestamp |\n+-------------+-------------+-------------+\n| 1 | 1 | 0 |\n| 1 | 1 | 1 |\n| 1 | 1 | 2 |\n| 1 | 2 | 3 |\n| 1 | 2 | 4 |\n| 2 | 1 | 5 |\n| 2 | 1 | 6 |\n+-------------+-------------+-------------+\n<strong>输出:</strong>\n+-------------+-------------+\n| actor_id | director_id |\n+-------------+-------------+\n| 1 | 1 |\n+-------------+-------------+\n<strong>解释:</strong>\n唯一的 id 对是 (1, 1),他们恰好合作了 3 次。</pre>\n",
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"insert into ActorDirector (actor_id, director_id, timestamp) values ('1', '1', '1')",
"insert into ActorDirector (actor_id, director_id, timestamp) values ('1', '1', '2')",
"insert into ActorDirector (actor_id, director_id, timestamp) values ('1', '2', '3')",
"insert into ActorDirector (actor_id, director_id, timestamp) values ('1', '2', '4')",
"insert into ActorDirector (actor_id, director_id, timestamp) values ('2', '1', '5')",
"insert into ActorDirector (actor_id, director_id, timestamp) values ('2', '1', '6')"
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