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56 lines
2.6 KiB
HTML
56 lines
2.6 KiB
HTML
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<p>You are given the customer visit log of a shop represented by a <strong>0-indexed</strong> string <code>customers</code> consisting only of characters <code>'N'</code> and <code>'Y'</code>:</p>
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<ul>
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<li>if the <code>i<sup>th</sup></code> character is <code>'Y'</code>, it means that customers come at the <code>i<sup>th</sup></code> hour</li>
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<li>whereas <code>'N'</code> indicates that no customers come at the <code>i<sup>th</sup></code> hour.</li>
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</ul>
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<p>If the shop closes at the <code>j<sup>th</sup></code> hour (<code>0 <= j <= n</code>), the <strong>penalty</strong> is calculated as follows:</p>
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<ul>
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<li>For every hour when the shop is open and no customers come, the penalty increases by <code>1</code>.</li>
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<li>For every hour when the shop is closed and customers come, the penalty increases by <code>1</code>.</li>
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</ul>
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<p>Return<em> the <strong>earliest</strong> hour at which the shop must be closed to incur a <strong>minimum</strong> penalty.</em></p>
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<p><strong>Note</strong> that if a shop closes at the <code>j<sup>th</sup></code> hour, it means the shop is closed at the hour <code>j</code>.</p>
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<p> </p>
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<p><strong class="example">Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> customers = "YYNY"
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<strong>Output:</strong> 2
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<strong>Explanation:</strong>
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- Closing the shop at the 0<sup>th</sup> hour incurs in 1+1+0+1 = 3 penalty.
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- Closing the shop at the 1<sup>st</sup> hour incurs in 0+1+0+1 = 2 penalty.
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- Closing the shop at the 2<sup>nd</sup> hour incurs in 0+0+0+1 = 1 penalty.
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- Closing the shop at the 3<sup>rd</sup> hour incurs in 0+0+1+1 = 2 penalty.
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- Closing the shop at the 4<sup>th</sup> hour incurs in 0+0+1+0 = 1 penalty.
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Closing the shop at 2<sup>nd</sup> or 4<sup>th</sup> hour gives a minimum penalty. Since 2 is earlier, the optimal closing time is 2.
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</pre>
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<p><strong class="example">Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> customers = "NNNNN"
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<strong>Output:</strong> 0
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<strong>Explanation:</strong> It is best to close the shop at the 0<sup>th</sup> hour as no customers arrive.</pre>
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<p><strong class="example">Example 3:</strong></p>
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<pre>
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<strong>Input:</strong> customers = "YYYY"
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<strong>Output:</strong> 4
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<strong>Explanation:</strong> It is best to close the shop at the 4<sup>th</sup> hour as customers arrive at each hour.
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</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code>1 <= customers.length <= 10<sup>5</sup></code></li>
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<li><code>customers</code> consists only of characters <code>'Y'</code> and <code>'N'</code>.</li>
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</ul>
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