2022-03-27 20:37:52 +08:00
< p > Given a 2D integer array < code > nums< / code > , return < em > all elements of < / em > < code > nums< / code > < em > in diagonal order as shown in the below images< / em > .< / p >
< p > < / p >
2023-12-09 18:42:21 +08:00
< p > < strong class = "example" > Example 1:< / strong > < / p >
2022-03-27 20:37:52 +08:00
< img alt = "" src = "https://assets.leetcode.com/uploads/2020/04/08/sample_1_1784.png" style = "width: 158px; height: 143px;" / >
< pre >
< strong > Input:< / strong > nums = [[1,2,3],[4,5,6],[7,8,9]]
< strong > Output:< / strong > [1,4,2,7,5,3,8,6,9]
< / pre >
2023-12-09 18:42:21 +08:00
< p > < strong class = "example" > Example 2:< / strong > < / p >
2022-03-27 20:37:52 +08:00
< img alt = "" src = "https://assets.leetcode.com/uploads/2020/04/08/sample_2_1784.png" style = "width: 230px; height: 177px;" / >
< pre >
< strong > Input:< / strong > nums = [[1,2,3,4,5],[6,7],[8],[9,10,11],[12,13,14,15,16]]
< strong > Output:< / strong > [1,6,2,8,7,3,9,4,12,10,5,13,11,14,15,16]
< / pre >
< p > < / p >
< p > < strong > Constraints:< / strong > < / p >
< ul >
< li > < code > 1 < = nums.length < = 10< sup > 5< / sup > < / code > < / li >
< li > < code > 1 < = nums[i].length < = 10< sup > 5< / sup > < / code > < / li >
< li > < code > 1 < = sum(nums[i].length) < = 10< sup > 5< / sup > < / code > < / li >
< li > < code > 1 < = nums[i][j] < = 10< sup > 5< / sup > < / code > < / li >
< / ul >