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leetcode-problemset/leetcode-cn/originData/find-the-longest-equal-subarray.json

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"categoryTitle": "Algorithms",
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"title": "Find the Longest Equal Subarray",
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"content": "<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> and an integer <code>k</code>.</p>\n\n<p>A subarray is called <strong>equal</strong> if all of its elements are equal. Note that the empty subarray is an <strong>equal</strong> subarray.</p>\n\n<p>Return <em>the length of the <strong>longest</strong> possible equal subarray after deleting <strong>at most</strong> </em><code>k</code><em> elements from </em><code>nums</code>.</p>\n\n<p>A <b>subarray</b> is a contiguous, possibly empty sequence of elements within an array.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,3,2,3,1,3], k = 3\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> It&#39;s optimal to delete the elements at index 2 and index 4.\nAfter deleting them, nums becomes equal to [1, 3, 3, 3].\nThe longest equal subarray starts at i = 1 and ends at j = 3 with length equal to 3.\nIt can be proven that no longer equal subarrays can be created.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,1,2,2,1,1], k = 2\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> It&#39;s optimal to delete the elements at index 2 and index 3.\nAfter deleting them, nums becomes equal to [1, 1, 1, 1].\nThe array itself is an equal subarray, so the answer is 4.\nIt can be proven that no longer equal subarrays can be created.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= nums.length</code></li>\n\t<li><code>0 &lt;= k &lt;= nums.length</code></li>\n</ul>\n",
"translatedTitle": "找出最长等值子数组",
"translatedContent": "<p>给你一个下标从 <strong>0</strong> 开始的整数数组 <code>nums</code> 和一个整数 <code>k</code> 。</p>\n\n<p>如果子数组中所有元素都相等,则认为子数组是一个 <strong>等值子数组</strong> 。注意,空数组是 <strong>等值子数组</strong> 。</p>\n\n<p>从 <code>nums</code> 中删除最多 <code>k</code> 个元素后,返回可能的最长等值子数组的长度。</p>\n\n<p><strong>子数组</strong> 是数组中一个连续且可能为空的元素序列。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [1,3,2,3,1,3], k = 3\n<strong>输出:</strong>3\n<strong>解释:</strong>最优的方案是删除下标 2 和下标 4 的元素。\n删除后nums 等于 [1, 3, 3, 3] 。\n最长等值子数组从 i = 1 开始到 j = 3 结束,长度等于 3 。\n可以证明无法创建更长的等值子数组。\n</pre>\n\n<p><strong class=\"example\">示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [1,1,2,2,1,1], k = 2\n<strong>输出:</strong>4\n<strong>解释:</strong>最优的方案是删除下标 2 和下标 3 的元素。 \n删除后nums 等于 [1, 1, 1, 1] 。 \n数组自身就是等值子数组长度等于 4 。 \n可以证明无法创建更长的等值子数组。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= nums.length</code></li>\n\t<li><code>0 &lt;= k &lt;= nums.length</code></li>\n</ul>\n",
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"<div class=\"_1l1MA\">For each number <code>x</code> in <code>nums</code>, create a sorted list <code>indices<sub>x</sub></code> of all indices <code>i</code> such that <code>nums[i] == x</code>.</div>",
"<div class=\"_1l1MA\">On every <code>indices<sub>x</sub></code>, execute a sliding window technique.</div>",
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