leetcode-problemset/leetcode/originData/maximum-number-of-fish-in-a-grid.json

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            "title": "Maximum Number of Fish in a Grid",
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            "content": "<p>You are given a <strong>0-indexed</strong> 2D matrix <code>grid</code> of size <code>m x n</code>, where <code>(r, c)</code> represents:</p>\n\n<ul>\n\t<li>A <strong>land</strong> cell if <code>grid[r][c] = 0</code>, or</li>\n\t<li>A <strong>water</strong> cell containing <code>grid[r][c]</code> fish, if <code>grid[r][c] &gt; 0</code>.</li>\n</ul>\n\n<p>A fisher can start at any <strong>water</strong> cell <code>(r, c)</code> and can do the following operations any number of times:</p>\n\n<ul>\n\t<li>Catch all the fish at cell <code>(r, c)</code>, or</li>\n\t<li>Move to any adjacent <strong>water</strong> cell.</li>\n</ul>\n\n<p>Return <em>the <strong>maximum</strong> number of fish the fisher can catch if he chooses his starting cell optimally, or </em><code>0</code> if no water cell exists.</p>\n\n<p>An <strong>adjacent</strong> cell of the cell <code>(r, c)</code>, is one of the cells <code>(r, c + 1)</code>, <code>(r, c - 1)</code>, <code>(r + 1, c)</code> or <code>(r - 1, c)</code> if it exists.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/03/29/example.png\" style=\"width: 241px; height: 161px;\" />\n<pre>\n<strong>Input:</strong> grid = [[0,2,1,0],[4,0,0,3],[1,0,0,4],[0,3,2,0]]\n<strong>Output:</strong> 7\n<strong>Explanation:</strong> The fisher can start at cell <code>(1,3)</code> and collect 3 fish, then move to cell <code>(2,3)</code>&nbsp;and collect 4 fish.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/03/29/example2.png\" />\n<pre>\n<strong>Input:</strong> grid = [[1,0,0,0],[0,0,0,0],[0,0,0,0],[0,0,0,1]]\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> The fisher can start at cells (0,0) or (3,3) and collect a single fish. \n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == grid.length</code></li>\n\t<li><code>n == grid[i].length</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 10</code></li>\n\t<li><code>0 &lt;= grid[i][j] &lt;= 10</code></li>\n</ul>\n",
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                    "lang": "C++",
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                    "code": "class Solution {\npublic:\n    int findMaxFish(vector<vector<int>>& grid) {\n        \n    }\n};",
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                    "code": "class Solution(object):\n    def findMaxFish(self, grid):\n        \"\"\"\n        :type grid: List[List[int]]\n        :rtype: int\n        \"\"\"\n        ",
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                    "code": "public class Solution {\n    public int FindMaxFish(int[][] grid) {\n        \n    }\n}",
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                    "code": "/**\n * @param {number[][]} grid\n * @return {number}\n */\nvar findMaxFish = function(grid) {\n    \n};",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer[][] $grid\n     * @return Integer\n     */\n    function findMaxFish($grid) {\n        \n    }\n}",
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                    "code": "func findMaxFish(grid [][]int) int {\n    \n}",
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                    "code": "# @param {Integer[][]} grid\n# @return {Integer}\ndef find_max_fish(grid)\n    \nend",
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                "Run DFS from each non-zero cell.",
                "Each time you pick a cell to start from, add up the number of fish contained in the cells you visit."
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