leetcode-problemset/leetcode-cn/problem (English)/包装数组(English) [array-wrapper].html

<p>Create a class&nbsp;<code>ArrayWrapper</code> that accepts&nbsp;an array of integers in its constructor. This class should have two features:</p>

<ul>
	<li>When two instances of this class are added together with the&nbsp;<code>+</code>&nbsp;operator, the resulting value is the sum of all the elements in&nbsp;both arrays.</li>
	<li>When the&nbsp;<code>String()</code>&nbsp;function is called on the instance, it will return a comma separated string surrounded by brackets. For example, <code>[1,2,3]</code>.</li>
</ul>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [[1,2],[3,4]], operation = &quot;Add&quot;
<strong>Output:</strong> 10
<strong>Explanation:</strong>
const obj1 = new ArrayWrapper([1,2]);
const obj2 = new ArrayWrapper([3,4]);
obj1 + obj2; // 10
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [[23,98,42,70]], operation = &quot;String&quot;
<strong>Output:</strong> &quot;[23,98,42,70]&quot;
<strong>Explanation:</strong>
const obj = new ArrayWrapper([23,98,42,70]);
String(obj); // &quot;[23,98,42,70]&quot;
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> nums = [[],[]], operation = &quot;Add&quot;
<strong>Output:</strong> 0
<strong>Explanation:</strong>
const obj1 = new ArrayWrapper([]);
const obj2 = new ArrayWrapper([]);
obj1 + obj2; // 0
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>0 &lt;= nums.length &lt;= 1000</code></li>
	<li><code>0 &lt;= nums[i]&nbsp;&lt;= 1000</code></li>
	<li><code>Note: nums is the array passed to the constructor</code></li>
</ul>