1
0
mirror of https://gitee.com/coder-xiaomo/leetcode-problemset synced 2025-01-27 02:30:28 +08:00
Code Issues Projects Releases Wiki Activity GitHub Gitee
leetcode-problemset/leetcode-cn/problem (Chinese)/是否所有 1 都至少相隔 k 个元素 [check-if-all-1s-are-at-least-length-k-places-away].html

42 lines
1.5 KiB
HTML
Raw Normal View History

2022-03-27 20:37:52 +08:00
<p>给你一个由若干 <code>0</code><code>1</code> 组成的数组 <code>nums</code> 以及整数 <code>k</code>。如果所有 <code>1</code> 都至少相隔 <code>k</code> 个元素,则返回 <code>True</code> ;否则,返回 <code>False</code></p>
<p>&nbsp;</p>
<p><strong>示例 1</strong></p>
<p><strong><img alt="" src="https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2020/05/03/sample_1_1791.png" style="width: 214px;"></strong></p>
<pre><strong>输入:</strong>nums = [1,0,0,0,1,0,0,1], k = 2
<strong>输出:</strong>true
<strong>解释:</strong>每个 1 都至少相隔 2 个元素。</pre>
<p><strong>示例 2</strong></p>
<p><strong><img alt="" src="https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2020/05/03/sample_2_1791.png" style="height: 86px; width: 160px;"></strong></p>
<pre><strong>输入:</strong>nums = [1,0,0,1,0,1], k = 2
<strong>输出:</strong>false
<strong>解释:</strong>第二个 1 和第三个 1 之间只隔了 1 个元素。</pre>
<p><strong>示例 3</strong></p>
<pre><strong>输入:</strong>nums = [1,1,1,1,1], k = 0
<strong>输出:</strong>true
</pre>
<p><strong>示例 4</strong></p>
<pre><strong>输入:</strong>nums = [0,1,0,1], k = 1
<strong>输出:</strong>true
</pre>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ul>
<li><code>1 &lt;= nums.length &lt;= 10^5</code></li>
<li><code>0 &lt;= k &lt;= nums.length</code></li>
<li><code>nums[i]</code> 的值为 <code>0</code><code>1</code></li>
</ul>