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leetcode-problemset/leetcode-cn/problem (Chinese)/统计一致字符串的数目 [count-the-number-of-consistent-strings].html

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<p>给你一个由不同字符组成的字符串 <code>allowed</code> 和一个字符串数组 <code>words</code> 。如果一个字符串的每一个字符都在 <code>allowed</code> 中,就称这个字符串是 <strong>一致字符串 </strong></p>
<p>请你返回 <code>words</code> 数组中 <strong>一致字符串</strong> 的数目。</p>
<p> </p>
<p><strong>示例 1</strong></p>
<pre>
<b>输入:</b>allowed = "ab", words = ["ad","bd","aaab","baa","badab"]
<b>输出:</b>2
<b>解释:</b>字符串 "aaab" 和 "baa" 都是一致字符串,因为它们只包含字符 'a' 和 'b' 。
</pre>
<p><strong>示例 2</strong></p>
<pre>
<b>输入:</b>allowed = "abc", words = ["a","b","c","ab","ac","bc","abc"]
<b>输出:</b>7
<b>解释:</b>所有字符串都是一致的。
</pre>
<p><strong>示例 3</strong></p>
<pre>
<b>输入:</b>allowed = "cad", words = ["cc","acd","b","ba","bac","bad","ac","d"]
<b>输出:</b>4
<b>解释:</b>字符串 "cc""acd""ac" 和 "d" 是一致字符串。
</pre>
<p> </p>
<p><strong>提示:</strong></p>
<ul>
<li><code>1 <= words.length <= 10<sup>4</sup></code></li>
<li><code>1 <= allowed.length <=<sup> </sup>26</code></li>
<li><code>1 <= words[i].length <= 10</code></li>
<li><code>allowed</code> 中的字符 <strong>互不相同</strong> 。</li>
<li><code>words[i]</code> 和 <code>allowed</code> 只包含小写英文字母。</li>
</ul>