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leetcode-problemset/leetcode-cn/problem (Chinese)/第 N 个泰波那契数 [n-th-tribonacci-number].html

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2022-03-27 20:37:52 +08:00
<p>泰波那契序列&nbsp;T<sub>n</sub>&nbsp;定义如下:&nbsp;</p>
<p>T<sub>0</sub> = 0, T<sub>1</sub> = 1, T<sub>2</sub> = 1, 且在 n &gt;= 0&nbsp;的条件下 T<sub>n+3</sub> = T<sub>n</sub> + T<sub>n+1</sub> + T<sub>n+2</sub></p>
<p>给你整数&nbsp;<code>n</code>,请返回第 n 个泰波那契数&nbsp;T<sub>n </sub>的值。</p>
<p>&nbsp;</p>
<p><strong>示例 1</strong></p>
<pre><strong>输入:</strong>n = 4
<strong>输出:</strong>4
<strong>解释:</strong>
T_3 = 0 + 1 + 1 = 2
T_4 = 1 + 1 + 2 = 4
</pre>
<p><strong>示例 2</strong></p>
<pre><strong>输入:</strong>n = 25
<strong>输出:</strong>1389537
</pre>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ul>
<li><code>0 &lt;= n &lt;= 37</code></li>
<li>答案保证是一个 32 位整数,即&nbsp;<code>answer &lt;= 2^31 - 1</code></li>
</ul>