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leetcode-problemset/leetcode-cn/problem (Chinese)/所有奇数长度子数组的和 [sum-of-all-odd-length-subarrays].html

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<p>给你一个正整数数组&nbsp;<code>arr</code>&nbsp;,请你计算所有可能的奇数长度子数组的和。</p>
<p><strong>子数组</strong> 定义为原数组中的一个连续子序列。</p>
<p>请你返回 <code>arr</code>&nbsp;<strong>所有奇数长度子数组的和</strong></p>
<p>&nbsp;</p>
<p><strong>示例 1</strong></p>
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<pre>
<strong>输入:</strong>arr = [1,4,2,5,3]
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<strong>输出:</strong>58
<strong>解释:</strong>所有奇数长度子数组和它们的和为:
[1] = 1
[4] = 4
[2] = 2
[5] = 5
[3] = 3
[1,4,2] = 7
[4,2,5] = 11
[2,5,3] = 10
[1,4,2,5,3] = 15
我们将所有值求和得到 1 + 4 + 2 + 5 + 3 + 7 + 11 + 10 + 15 = 58</pre>
<p><strong>示例 2</strong></p>
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<pre>
<strong>输入:</strong>arr = [1,2]
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<strong>输出:</strong>3
<strong>解释:</strong>总共只有 2 个长度为奇数的子数组,[1] 和 [2]。它们的和为 3 。</pre>
<p><strong>示例 3</strong></p>
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<pre>
<strong>输入:</strong>arr = [10,11,12]
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<strong>输出:</strong>66
</pre>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ul>
<li><code>1 &lt;= arr.length &lt;= 100</code></li>
<li><code>1 &lt;= arr[i] &lt;= 1000</code></li>
</ul>
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<p>&nbsp;</p>
<p><strong>进阶:</strong></p>
<p>你可以设计一个 O(n) 时间复杂度的算法解决此问题吗?</p>