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30 lines
1015 B
HTML
30 lines
1015 B
HTML
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<p>给你一个链表的头节点 <code>head</code> 和一个特定值<em> </em><code>x</code> ，请你对链表进行分隔，使得所有 <strong>小于</strong> <code>x</code> 的节点都出现在 <strong>大于或等于</strong> <code>x</code> 的节点之前。</p>
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<p>你不需要 <strong>保留</strong> 每个分区中各节点的初始相对位置。</p>
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<p> </p>
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<p><strong>示例 1：</strong></p>
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<img alt="" src="https://assets.leetcode.com/uploads/2021/01/04/partition.jpg" style="width: 662px; height: 222px;" />
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<pre>
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<strong>输入：</strong>head = [1,4,3,2,5,2], x = 3
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<strong>输出</strong>：[1,2,2,4,3,5]
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</pre>
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<p><strong>示例 2：</strong></p>
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<pre>
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<strong>输入：</strong>head = [2,1], x = 2
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<strong>输出</strong>：[1,2]
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</pre>
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<p> </p>
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<p><strong>提示：</strong></p>
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<ul>
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<li>链表中节点的数目在范围 <code>[0, 200]</code> 内</li>
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<li><code>-100 <= Node.val <= 100</code></li>
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<li><code>-200 <= x <= 200</code></li>
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</ul>
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