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leetcode-problemset/leetcode-cn/problem (Chinese)/元素和小于等于阈值的正方形的最大边长 [maximum-side-length-of-a-square-with-sum-less-than-or-equal-to-threshold].html

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2022-03-27 20:37:52 +08:00
<p>给你一个大小为&nbsp;<code>m x n</code>&nbsp;的矩阵&nbsp;<code>mat</code>&nbsp;和一个整数阈值&nbsp;<code>threshold</code></p>
<p>请你返回元素总和小于或等于阈值的正方形区域的最大边长;如果没有这样的正方形区域,则返回 <strong>0&nbsp;</strong><br />
&nbsp;</p>
<p><strong>示例 1</strong></p>
<p><img alt="" src="https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2019/12/15/e1.png" style="height: 186px; width: 335px;" /></p>
<pre>
<strong>输入:</strong>mat = [[1,1,3,2,4,3,2],[1,1,3,2,4,3,2],[1,1,3,2,4,3,2]], threshold = 4
<strong>输出:</strong>2
<strong>解释:</strong>总和小于或等于 4 的正方形的最大边长为 2如图所示。
</pre>
<p><strong>示例 2</strong></p>
<pre>
<strong>输入:</strong>mat = [[2,2,2,2,2],[2,2,2,2,2],[2,2,2,2,2],[2,2,2,2,2],[2,2,2,2,2]], threshold = 1
<strong>输出:</strong>0
</pre>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ul>
<li><code>m == mat.length</code></li>
<li><code>n == mat[i].length</code></li>
<li><code>1 &lt;= m, n &lt;= 300</code></li>
<li><code>0 &lt;= mat[i][j] &lt;= 10<sup>4</sup></code></li>
<li><code>0 &lt;= threshold &lt;= 10<sup>5</sup></code><sup>&nbsp;</sup></li>
</ul>