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2022-03-27 20:38:29 +08:00
<p>实现一个 <code>MapSum</code> 类,支持两个方法,<code>insert</code>&nbsp;&nbsp;<code>sum</code></p>
<ul>
<li><code>MapSum()</code> 初始化 <code>MapSum</code> 对象</li>
<li><code>void insert(String key, int val)</code> 插入 <code>key-val</code> 键值对,字符串表示键 <code>key</code> ,整数表示值 <code>val</code> 。如果键 <code>key</code> 已经存在,那么原来的键值对将被替代成新的键值对。</li>
<li><code>int sum(string prefix)</code> 返回所有以该前缀 <code>prefix</code> 开头的键 <code>key</code> 的值的总和。</li>
</ul>
<p>&nbsp;</p>
<p><strong>示例:</strong></p>
<pre>
<strong>输入:</strong>
inputs = [&quot;MapSum&quot;, &quot;insert&quot;, &quot;sum&quot;, &quot;insert&quot;, &quot;sum&quot;]
inputs = [[], [&quot;apple&quot;, 3], [&quot;ap&quot;], [&quot;app&quot;, 2], [&quot;ap&quot;]]
<strong>输出:</strong>
[null, null, 3, null, 5]
<strong>解释:</strong>
MapSum mapSum = new MapSum();
mapSum.insert(&quot;apple&quot;, 3);
mapSum.sum(&quot;ap&quot;); // return 3 (<u>ap</u>ple = 3)
mapSum.insert(&quot;app&quot;, 2);
mapSum.sum(&quot;ap&quot;); // return 5 (<u>ap</u>ple + <u>ap</u>p = 3 + 2 = 5)
</pre>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ul>
<li><code>1 &lt;= key.length, prefix.length &lt;= 50</code></li>
<li><code>key</code><code>prefix</code> 仅由小写英文字母组成</li>
<li><code>1 &lt;= val &lt;= 1000</code></li>
<li>最多调用 <code>50</code><code>insert</code><code>sum</code></li>
</ul>
<p>&nbsp;</p>
<p><meta charset="UTF-8" />注意:本题与主站 677&nbsp;题相同:&nbsp;<a href="https://leetcode-cn.com/problems/map-sum-pairs/">https://leetcode-cn.com/problems/map-sum-pairs/</a></p>