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48 lines
1.4 KiB
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48 lines
1.4 KiB
HTML
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<p>给你两个字符串 <code>word1</code> 和 <code>word2</code> 。请你从 <code>word1</code> 开始，通过交替添加字母来合并字符串。如果一个字符串比另一个字符串长，就将多出来的字母追加到合并后字符串的末尾。</p>
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<p>返回 <strong>合并后的字符串</strong> 。</p>
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<p> </p>
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<p><strong>示例 1：</strong></p>
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<pre>
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<strong>输入：</strong>word1 = "abc", word2 = "pqr"
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<strong>输出：</strong>"apbqcr"
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<strong>解释：</strong>字符串合并情况如下所示：
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word1： a b c
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word2： p q r
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合并后： a p b q c r
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</pre>
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<p><strong>示例 2：</strong></p>
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<pre>
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<strong>输入：</strong>word1 = "ab", word2 = "pqrs"
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<strong>输出：</strong>"apbqrs"
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<strong>解释：</strong>注意，word2 比 word1 长，"rs" 需要追加到合并后字符串的末尾。
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word1： a b
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word2： p q r s
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合并后： a p b q r s
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</pre>
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<p><strong>示例 3：</strong></p>
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<pre>
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<strong>输入：</strong>word1 = "abcd", word2 = "pq"
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<strong>输出：</strong>"apbqcd"
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<strong>解释：</strong>注意，word1 比 word2 长，"cd" 需要追加到合并后字符串的末尾。
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word1： a b c d
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word2： p q
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合并后： a p b q c d
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</pre>
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<p> </p>
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<p><strong>提示：</strong></p>
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<ul>
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<li><code>1 <= word1.length, word2.length <= 100</code></li>
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<li><code>word1</code> 和 <code>word2</code> 由小写英文字母组成</li>
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</ul>
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