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43 lines
1.8 KiB
HTML
43 lines
1.8 KiB
HTML
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<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> and an integer <code>k</code>. You have a <strong>starting score</strong> of <code>0</code>.</p>
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<p>In one <strong>operation</strong>:</p>
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<ol>
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<li>choose an index <code>i</code> such that <code>0 <= i < nums.length</code>,</li>
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<li>increase your <strong>score</strong> by <code>nums[i]</code>, and</li>
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<li>replace <code>nums[i]</code> with <code>ceil(nums[i] / 3)</code>.</li>
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</ol>
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<p>Return <em>the maximum possible <strong>score</strong> you can attain after applying <strong>exactly</strong></em> <code>k</code> <em>operations</em>.</p>
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<p>The ceiling function <code>ceil(val)</code> is the least integer greater than or equal to <code>val</code>.</p>
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<p> </p>
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<p><strong>Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> nums = [10,10,10,10,10], k = 5
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<strong>Output:</strong> 50
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<strong>Explanation:</strong> Apply the operation to each array element exactly once. The final score is 10 + 10 + 10 + 10 + 10 = 50.
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</pre>
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<p><strong>Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> nums = [1,10,3,3,3], k = 3
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<strong>Output:</strong> 17
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<strong>Explanation: </strong>You can do the following operations:
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Operation 1: Select i = 1, so nums becomes [1,<strong><u>4</u></strong>,3,3,3]. Your score increases by 10.
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Operation 2: Select i = 1, so nums becomes [1,<strong><u>2</u></strong>,3,3,3]. Your score increases by 4.
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Operation 3: Select i = 2, so nums becomes [1,1,<u><strong>1</strong></u>,3,3]. Your score increases by 3.
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The final score is 10 + 4 + 3 = 17.
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</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code>1 <= nums.length, k <= 10<sup>5</sup></code></li>
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<li><code>1 <= nums[i] <= 10<sup>9</sup></code></li>
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</ul>
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