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leetcode-problemset/leetcode/originData/closest-prime-numbers-in-range.json

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{
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"title": "Closest Prime Numbers in Range",
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"content": "<p>Given two positive integers <code>left</code> and <code>right</code>, find the two integers <code>num1</code> and <code>num2</code> such that:</p>\n\n<ul>\n\t<li><code>left &lt;= nums1 &lt; nums2 &lt;= right </code>.</li>\n\t<li><code>nums1</code> and <code>nums2</code> are both <strong>prime</strong> numbers.</li>\n\t<li><code>nums2 - nums1</code> is the <strong>minimum</strong> amongst all other pairs satisfying the above conditions.</li>\n</ul>\n\n<p>Return <em>the positive integer array</em> <code>ans = [nums1, nums2]</code>. <em>If there are multiple pairs satisfying these conditions, return the one with the minimum</em> <code>nums1</code> <em>value or</em> <code>[-1, -1]</code> <em>if such numbers do not exist.</em></p>\n\n<p>A number greater than <code>1</code> is called <b>prime</b> if it is only divisible by <code>1</code> and itself.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> left = 10, right = 19\n<strong>Output:</strong> [11,13]\n<strong>Explanation:</strong> The prime numbers between 10 and 19 are 11, 13, 17, and 19.\nThe closest gap between any pair is 2, which can be achieved by [11,13] or [17,19].\nSince 11 is smaller than 17, we return the first pair.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> left = 4, right = 6\n<strong>Output:</strong> [-1,-1]\n<strong>Explanation:</strong> There exists only one prime number in the given range, so the conditions cannot be satisfied.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= left &lt;= right &lt;= 10<sup>6</sup></code></li>\n</ul>\n\n<p>&nbsp;</p>\n<style type=\"text/css\">.spoilerbutton {display:block; border:dashed; padding: 0px 0px; margin:10px 0px; font-size:150%; font-weight: bold; color:#000000; background-color:cyan; outline:0; \n}\n.spoiler {overflow:hidden;}\n.spoiler > div {-webkit-transition: all 0s ease;-moz-transition: margin 0s ease;-o-transition: all 0s ease;transition: margin 0s ease;}\n.spoilerbutton[value=\"Show Message\"] + .spoiler > div {margin-top:-500%;}\n.spoilerbutton[value=\"Hide Message\"] + .spoiler {padding:5px;}\n</style>\n",
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"code": "class Solution {\npublic:\n vector<int> closestPrimes(int left, int right) {\n \n }\n};",
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"code": "class Solution(object):\n def closestPrimes(self, left, right):\n \"\"\"\n :type left: int\n :type right: int\n :rtype: List[int]\n \"\"\"\n ",
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"code": "/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nint* closestPrimes(int left, int right, int* returnSize) {\n \n}",
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"code": "/**\n * @param {number} left\n * @param {number} right\n * @return {number[]}\n */\nvar closestPrimes = function(left, right) {\n \n};",
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"code": "impl Solution {\n pub fn closest_primes(left: i32, right: i32) -> Vec<i32> {\n \n }\n}",
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"code": "(define/contract (closest-primes left right)\n (-> exact-integer? exact-integer? (listof exact-integer?))\n )",
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"code": "defmodule Solution do\n @spec closest_primes(left :: integer, right :: integer) :: [integer]\n def closest_primes(left, right) do\n \n end\nend",
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"hints": [
"Use Sieve of Eratosthenes to mark numbers that are primes.",
"Iterate from right to left and find pair with the minimum distance between marked numbers."
],
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"sampleTestCase": "10\n19",
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