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            "questionId": "1378",
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            "title": "Cells with Odd Values in a Matrix",
            "titleSlug": "cells-with-odd-values-in-a-matrix",
            "content": "<p>There is an <code>m x n</code> matrix that is initialized to all <code>0</code>&#39;s. There is also a 2D array <code>indices</code> where each <code>indices[i] = [r<sub>i</sub>, c<sub>i</sub>]</code> represents a <strong>0-indexed location</strong> to perform some increment operations on the matrix.</p>\n\n<p>For each location <code>indices[i]</code>, do <strong>both</strong> of the following:</p>\n\n<ol>\n\t<li>Increment <strong>all</strong> the cells on row <code>r<sub>i</sub></code>.</li>\n\t<li>Increment <strong>all</strong> the cells on column <code>c<sub>i</sub></code>.</li>\n</ol>\n\n<p>Given <code>m</code>, <code>n</code>, and <code>indices</code>, return <em>the <strong>number of odd-valued cells</strong> in the matrix after applying the increment to all locations in </em><code>indices</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/10/30/e1.png\" style=\"width: 600px; height: 118px;\" />\n<pre>\n<strong>Input:</strong> m = 2, n = 3, indices = [[0,1],[1,1]]\n<strong>Output:</strong> 6\n<strong>Explanation:</strong> Initial matrix = [[0,0,0],[0,0,0]].\nAfter applying first increment it becomes [[1,2,1],[0,1,0]].\nThe final matrix is [[1,3,1],[1,3,1]], which contains 6 odd numbers.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/10/30/e2.png\" style=\"width: 600px; height: 150px;\" />\n<pre>\n<strong>Input:</strong> m = 2, n = 2, indices = [[1,1],[0,0]]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> Final matrix = [[2,2],[2,2]]. There are no odd numbers in the final matrix.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= m, n &lt;= 50</code></li>\n\t<li><code>1 &lt;= indices.length &lt;= 100</code></li>\n\t<li><code>0 &lt;= r<sub>i</sub> &lt; m</code></li>\n\t<li><code>0 &lt;= c<sub>i</sub> &lt; n</code></li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong>Follow up:</strong> Could you solve this in <code>O(n + m + indices.length)</code> time with only <code>O(n + m)</code> extra space?</p>\n",
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                    "code": "class Solution {\npublic:\n    int oddCells(int m, int n, vector<vector<int>>& indices) {\n        \n    }\n};",
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                    "code": "class Solution {\n    public int oddCells(int m, int n, int[][] indices) {\n        \n    }\n}",
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                    "code": "class Solution(object):\n    def oddCells(self, m, n, indices):\n        \"\"\"\n        :type m: int\n        :type n: int\n        :type indices: List[List[int]]\n        :rtype: int\n        \"\"\"\n        ",
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                    "code": "class Solution:\n    def oddCells(self, m: int, n: int, indices: List[List[int]]) -> int:\n        ",
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                    "code": "public class Solution {\n    public int OddCells(int m, int n, int[][] indices) {\n        \n    }\n}",
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                    "code": "/**\n * @param {number} m\n * @param {number} n\n * @param {number[][]} indices\n * @return {number}\n */\nvar oddCells = function(m, n, indices) {\n    \n};",
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                    "code": "# @param {Integer} m\n# @param {Integer} n\n# @param {Integer[][]} indices\n# @return {Integer}\ndef odd_cells(m, n, indices)\n    \nend",
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                    "code": "class Solution {\n    func oddCells(_ m: Int, _ n: Int, _ indices: [[Int]]) -> Int {\n        \n    }\n}",
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                    "code": "func oddCells(m int, n int, indices [][]int) int {\n    \n}",
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                    "code": "object Solution {\n    def oddCells(m: Int, n: Int, indices: Array[Array[Int]]): Int = {\n        \n    }\n}",
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                    "code": "class Solution {\n    fun oddCells(m: Int, n: Int, indices: Array<IntArray>): Int {\n        \n    }\n}",
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                    "code": "impl Solution {\n    pub fn odd_cells(m: i32, n: i32, indices: Vec<Vec<i32>>) -> i32 {\n        \n    }\n}",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer $m\n     * @param Integer $n\n     * @param Integer[][] $indices\n     * @return Integer\n     */\n    function oddCells($m, $n, $indices) {\n        \n    }\n}",
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                    "code": "(define/contract (odd-cells m n indices)\n  (-> exact-integer? exact-integer? (listof (listof exact-integer?)) exact-integer?)\n\n  )",
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                    "code": "-spec odd_cells(M :: integer(), N :: integer(), Indices :: [[integer()]]) -> integer().\nodd_cells(M, N, Indices) ->\n  .",
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                    "code": "defmodule Solution do\n  @spec odd_cells(m :: integer, n :: integer, indices :: [[integer]]) :: integer\n  def odd_cells(m, n, indices) do\n\n  end\nend",
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            "hints": [
                "Simulation : With small constraints, it is possible to apply changes to each row and column and count odd cells after applying it.",
                "You can accumulate the number you should add to each row and column and then you can count the number of odd cells."
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