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            "title": "Minimum Operations to Make the Array Alternating",
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            "content": "<p>You are given a <strong>0-indexed</strong> array <code>nums</code> consisting of <code>n</code> positive integers.</p>\n\n<p>The array <code>nums</code> is called <strong>alternating</strong> if:</p>\n\n<ul>\n\t<li><code>nums[i - 2] == nums[i]</code>, where <code>2 &lt;= i &lt;= n - 1</code>.</li>\n\t<li><code>nums[i - 1] != nums[i]</code>, where <code>1 &lt;= i &lt;= n - 1</code>.</li>\n</ul>\n\n<p>In one <strong>operation</strong>, you can choose an index <code>i</code> and <strong>change</strong> <code>nums[i]</code> into <strong>any</strong> positive integer.</p>\n\n<p>Return <em>the <strong>minimum number of operations</strong> required to make the array alternating</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,1,3,2,4,3]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong>\nOne way to make the array alternating is by converting it to [3,1,3,<u><strong>1</strong></u>,<u><strong>3</strong></u>,<u><strong>1</strong></u>].\nThe number of operations required in this case is 3.\nIt can be proven that it is not possible to make the array alternating in less than 3 operations. \n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,2,2,2]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong>\nOne way to make the array alternating is by converting it to [1,2,<u><strong>1</strong></u>,2,<u><strong>1</strong></u>].\nThe number of operations required in this case is 2.\nNote that the array cannot be converted to [<u><strong>2</strong></u>,2,2,2,2] because in this case nums[0] == nums[1] which violates the conditions of an alternating array.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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                "Count the frequency of each element in odd positions in the array. Do the same for elements in even positions.",
                "To minimize the number of operations we need to maximize the number of elements we keep from the original array.",
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