You are given an integer array `nums` and an array `queries` where `queries[i] = [vali, indexi]`.

For each query `i`, first, apply `nums[indexi] = nums[indexi] + vali`, then print the sum of the even values of `nums`.

Return an integer array `answer` where `answer[i]` is the answer to the `ith` query.

Example 1:

    Input: nums = [1,2,3,4], queries = [[1,0],[-3,1],[-4,0],[2,3]]
    Output: [8,6,2,4]
    Explanation: At the beginning, the array is [1,2,3,4].
    After adding 1 to nums[0], the array is [2,2,3,4], and the sum of even values is 2 + 2 + 4 = 8.
    After adding -3 to nums[1], the array is [2,-1,3,4], and the sum of even values is 2 + 4 = 6.
    After adding -4 to nums[0], the array is [-2,-1,3,4], and the sum of even values is -2 + 4 = 2.
    After adding 2 to nums[3], the array is [-2,-1,3,6], and the sum of even values is -2 + 6 = 4.

Example 2:

    Input: nums = [1], queries = [[4,0]]
    Output: [0]

Constraints:

- `1 <= nums.length <= 104`
- `-104 <= nums[i] <= 104`
- `1 <= queries.length <= 104`
- `-104 <= vali <= 104`
- `0 <= indexi < nums.length`