You are given the logs for users' actions on LeetCode, and an integer `k`. The logs are represented by a 2D integer array `logs` where each `logs[i] = [IDi, timei]` indicates that the user with `IDi` performed an action at the minute `timei`.

Multiple users can perform actions simultaneously, and a single user can perform multiple actions in the same minute.

The user active minutes (UAM) for a given user is defined as the number of unique minutes in which the user performed an action on LeetCode. A minute can only be counted once, even if multiple actions occur during it.

You are to calculate a 1-indexed array `answer` of size `k` such that, for each `j` (`1 <= j <= k`), `answer[j]` is the number of users whose UAM equals `j`.

Return the array `answer` as described above.

Example 1:

    Input: logs = [[0,5],[1,2],[0,2],[0,5],[1,3]], k = 5
    Output: [0,2,0,0,0]
    Explanation:
    The user with ID=0 performed actions at minutes 5, 2, and 5 again. Hence, they have a UAM of 2 (minute 5 is only counted once).
    The user with ID=1 performed actions at minutes 2 and 3. Hence, they have a UAM of 2.
    Since both users have a UAM of 2, answer[2] is 2, and the remaining answer[j] values are 0.

Example 2:

    Input: logs = [[1,1],[2,2],[2,3]], k = 4
    Output: [1,1,0,0]
    Explanation:
    The user with ID=1 performed a single action at minute 1. Hence, they have a UAM of 1.
    The user with ID=2 performed actions at minutes 2 and 3. Hence, they have a UAM of 2.
    There is one user with a UAM of 1 and one with a UAM of 2.
    Hence, answer[1] = 1, answer[2] = 1, and the remaining values are 0.

Constraints:

- `1 <= logs.length <= 104`
- `0 <= IDi <= 109`
- `1 <= timei <= 105`
- `k` is in the range `[The maximum UAM for a user, 105]`.