You are given a 0-indexed integer array `nums`. Rearrange the values of `nums` according to the following rules:

1. Sort the values at odd indices of `nums` in non-increasing order.
   - For example, if `nums = [4,1,2,3]` before this step, it becomes `[4,3,2,1]` after. The values at odd indices `1` and `3` are sorted in non-increasing order.
2. Sort the values at even indices of `nums` in non-decreasing order.
   - For example, if `nums = [4,1,2,3]` before this step, it becomes `[2,1,4,3]` after. The values at even indices `0` and `2` are sorted in non-decreasing order.

Return the array formed after rearranging the values of `nums`.

Example 1:

    Input: nums = [4,1,2,3]
    Output: [2,3,4,1]
    Explanation:
    First, we sort the values present at odd indices (1 and 3) in non-increasing order.
    So, nums changes from [4,1,2,3] to [4,3,2,1].
    Next, we sort the values present at even indices (0 and 2) in non-decreasing order.
    So, nums changes from [4,1,2,3] to [2,3,4,1].
    Thus, the array formed after rearranging the values is [2,3,4,1].

Example 2:

    Input: nums = [2,1]
    Output: [2,1]
    Explanation:
    Since there is exactly one odd index and one even index, no rearrangement of values takes place.
    The resultant array formed is [2,1], which is the same as the initial array.

Constraints:

- `1 <= nums.length <= 100`
- `1 <= nums[i] <= 100`