You are given an array of positive integers `beans`, where each integer represents the number of magic beans found in a particular magic bag.

Remove any number of beans (possibly none) from each bag such that the number of beans in each remaining non-empty bag (still containing at least one bean) is equal. Once a bean has been removed from a bag, you are not allowed to return it to any of the bags.

Return the minimum number of magic beans that you have to remove.

Example 1:

    Input: beans = [4,1,6,5]
    Output: 4
    Explanation:
    - We remove 1 bean from the bag with only 1 bean.
      This results in the remaining bags: [4,0,6,5]
    - Then we remove 2 beans from the bag with 6 beans.
      This results in the remaining bags: [4,0,4,5]
    - Then we remove 1 bean from the bag with 5 beans.
      This results in the remaining bags: [4,0,4,4]
    We removed a total of 1 + 2 + 1 = 4 beans to make the remaining non-empty bags have an equal number of beans.
    There are no other solutions that remove 4 beans or fewer.

Example 2:

    Input: beans = [2,10,3,2]
    Output: 7
    Explanation:
    - We remove 2 beans from one of the bags with 2 beans.
      This results in the remaining bags: [0,10,3,2]
    - Then we remove 2 beans from the other bag with 2 beans.
      This results in the remaining bags: [0,10,3,0]
    - Then we remove 3 beans from the bag with 3 beans.
      This results in the remaining bags: [0,10,0,0]
    We removed a total of 2 + 2 + 3 = 7 beans to make the remaining non-empty bags have an equal number of beans.
    There are no other solutions that removes 7 beans or fewer.

Constraints:

- `1 <= beans.length <= 105`
- `1 <= beans[i] <= 105`