Suppose an array of length `n` sorted in ascending order is rotated between `1` and `n` times. For example, the array `nums = [0,1,2,4,5,6,7]` might become:

- `[4,5,6,7,0,1,2]` if it was rotated `4` times.
- `[0,1,2,4,5,6,7]` if it was rotated `7` times.

Notice that rotating an array `[a[0], a[1], a[2], ..., a[n-1]]` 1 time results in the array `[a[n-1], a[0], a[1], a[2], ..., a[n-2]]`.

Given the sorted rotated array `nums` of unique elements, return the minimum element of this array.

You must write an algorithm that runs in `O(log n) time.`

Example 1:

    Input: nums = [3,4,5,1,2]
    Output: 1
    Explanation: The original array was [1,2,3,4,5] rotated 3 times.

Example 2:

    Input: nums = [4,5,6,7,0,1,2]
    Output: 0
    Explanation: The original array was [0,1,2,4,5,6,7] and it was rotated 4 times.

Example 3:

    Input: nums = [11,13,15,17]
    Output: 11
    Explanation: The original array was [11,13,15,17] and it was rotated 4 times.

Constraints:

- `n == nums.length`
- `1 <= n <= 5000`
- `-5000 <= nums[i] <= 5000`
- All the integers of `nums` are unique.
- `nums` is sorted and rotated between `1` and `n` times.