A string is a valid parentheses string (denoted VPS) if and only if it consists of `"("` and `")"` characters only, and:

- It is the empty string, or
- It can be written as `AB` (`A` concatenated with `B`), where `A` and `B` are VPS's, or
- It can be written as `(A)`, where `A` is a VPS.

We can similarly define the nesting depth `depth(S)` of any VPS `S` as follows:

- `depth("") = 0`
- `depth(A + B) = max(depth(A), depth(B))`, where `A` and `B` are VPS's
- `depth("(" + A + ")") = 1 + depth(A)`, where `A` is a VPS.

For example, `""`, `"()()"`, and `"()(()())"` are VPS's (with nesting depths 0, 1, and 2), and `")("` and `"(()"` are not VPS's.

Given a VPS seq, split it into two disjoint subsequences `A` and `B`, such that `A` and `B` are VPS's (and `A.length + B.length = seq.length`).

Now choose any such `A` and `B` such that `max(depth(A), depth(B))` is the minimum possible value.

Return an `answer` array (of length `seq.length`) that encodes such a choice of `A` and `B`: `answer[i] = 0` if `seq[i]` is part of `A`, else `answer[i] = 1`. Note that even though multiple answers may exist, you may return any of them.

Example 1:

    Input: seq = "(()())"
    Output: [0,1,1,1,1,0]

Example 2:

    Input: seq = "()(())()"
    Output: [0,0,0,1,1,0,1,1]

Constraints:

- `1 <= seq.size <= 10000`