You are given an integer array `nums`. The absolute sum of a subarray `[numsl, numsl+1, ..., numsr-1, numsr]` is `abs(numsl + numsl+1 + ... + numsr-1 + numsr)`.

Return the maximum absolute sum of any (possibly empty) subarray of `nums`.

Note that `abs(x)` is defined as follows:

- If `x` is a negative integer, then `abs(x) = -x`.
- If `x` is a non-negative integer, then `abs(x) = x`.

Example 1:

    Input: nums = [1,-3,2,3,-4]
    Output: 5
    Explanation: The subarray [2,3] has absolute sum = abs(2+3) = abs(5) = 5.

Example 2:

    Input: nums = [2,-5,1,-4,3,-2]
    Output: 8
    Explanation: The subarray [-5,1,-4] has absolute sum = abs(-5+1-4) = abs(-8) = 8.

Constraints:

- `1 <= nums.length <= 105`
- `-104 <= nums[i] <= 104`