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            "title": "Two Best Non-Overlapping Events",
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            "content": "<p>You are given a <strong>0-indexed</strong> 2D integer array of <code>events</code> where <code>events[i] = [startTime<sub>i</sub>, endTime<sub>i</sub>, value<sub>i</sub>]</code>. The <code>i<sup>th</sup></code> event starts at <code>startTime<sub>i</sub></code><sub> </sub>and ends at <code>endTime<sub>i</sub></code>, and if you attend this event, you will receive a value of <code>value<sub>i</sub></code>. You can choose <strong>at most</strong> <strong>two</strong> <strong>non-overlapping</strong> events to attend such that the sum of their values is <strong>maximized</strong>.</p>\n\n<p>Return <em>this <strong>maximum</strong> sum.</em></p>\n\n<p>Note that the start time and end time is <strong>inclusive</strong>: that is, you cannot attend two events where one of them starts and the other ends at the same time. More specifically, if you attend an event with end time <code>t</code>, the next event must start at or after <code>t + 1</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/09/21/picture5.png\" style=\"width: 400px; height: 75px;\" />\n<pre>\n<strong>Input:</strong> events = [[1,3,2],[4,5,2],[2,4,3]]\n<strong>Output:</strong> 4\n<strong>Explanation: </strong>Choose the green events, 0 and 1 for a sum of 2 + 2 = 4.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n<img alt=\"Example 1 Diagram\" src=\"https://assets.leetcode.com/uploads/2021/09/21/picture1.png\" style=\"width: 400px; height: 77px;\" />\n<pre>\n<strong>Input:</strong> events = [[1,3,2],[4,5,2],[1,5,5]]\n<strong>Output:</strong> 5\n<strong>Explanation: </strong>Choose event 2 for a sum of 5.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/09/21/picture3.png\" style=\"width: 400px; height: 66px;\" />\n<pre>\n<strong>Input:</strong> events = [[1,5,3],[1,5,1],[6,6,5]]\n<strong>Output:</strong> 8\n<strong>Explanation: </strong>Choose events 0 and 2 for a sum of 3 + 5 = 8.</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= events.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>events[i].length == 3</code></li>\n\t<li><code>1 &lt;= startTime<sub>i</sub> &lt;= endTime<sub>i</sub> &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= value<sub>i</sub> &lt;= 10<sup>6</sup></code></li>\n</ul>\n",
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                    "code": "class Solution(object):\n    def maxTwoEvents(self, events):\n        \"\"\"\n        :type events: List[List[int]]\n        :rtype: int\n        \"\"\"\n        ",
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                    "code": "# @param {Integer[][]} events\n# @return {Integer}\ndef max_two_events(events)\n    \nend",
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                    "code": "class Solution {\n    func maxTwoEvents(_ events: [[Int]]) -> Int {\n        \n    }\n}",
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                    "code": "impl Solution {\n    pub fn max_two_events(events: Vec<Vec<i32>>) -> i32 {\n        \n    }\n}",
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            "hints": [
                "How can sorting the events on the basis of their start times help? How about end times?",
                "How can we quickly get the maximum score of an interval not intersecting with the interval we chose?"
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