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            "title": "Minimum Number of Days to Make m Bouquets",
            "titleSlug": "minimum-number-of-days-to-make-m-bouquets",
            "content": "<p>You are given an integer array <code>bloomDay</code>, an integer <code>m</code> and an integer <code>k</code>.</p>\n\n<p>You want to make <code>m</code> bouquets. To make a bouquet, you need to use <code>k</code> <strong>adjacent flowers</strong> from the garden.</p>\n\n<p>The garden consists of <code>n</code> flowers, the <code>i<sup>th</sup></code> flower will bloom in the <code>bloomDay[i]</code> and then can be used in <strong>exactly one</strong> bouquet.</p>\n\n<p>Return <em>the minimum number of days you need to wait to be able to make </em><code>m</code><em> bouquets from the garden</em>. If it is impossible to make m bouquets return <code>-1</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> bloomDay = [1,10,3,10,2], m = 3, k = 1\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> Let us see what happened in the first three days. x means flower bloomed and _ means flower did not bloom in the garden.\nWe need 3 bouquets each should contain 1 flower.\nAfter day 1: [x, _, _, _, _]   // we can only make one bouquet.\nAfter day 2: [x, _, _, _, x]   // we can only make two bouquets.\nAfter day 3: [x, _, x, _, x]   // we can make 3 bouquets. The answer is 3.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> bloomDay = [1,10,3,10,2], m = 3, k = 2\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> We need 3 bouquets each has 2 flowers, that means we need 6 flowers. We only have 5 flowers so it is impossible to get the needed bouquets and we return -1.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> bloomDay = [7,7,7,7,12,7,7], m = 2, k = 3\n<strong>Output:</strong> 12\n<strong>Explanation:</strong> We need 2 bouquets each should have 3 flowers.\nHere is the garden after the 7 and 12 days:\nAfter day 7: [x, x, x, x, _, x, x]\nWe can make one bouquet of the first three flowers that bloomed. We cannot make another bouquet from the last three flowers that bloomed because they are not adjacent.\nAfter day 12: [x, x, x, x, x, x, x]\nIt is obvious that we can make two bouquets in different ways.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>bloomDay.length == n</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= bloomDay[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= m &lt;= 10<sup>6</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= n</code></li>\n</ul>\n",
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                    "lang": "C++",
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                    "code": "class Solution {\npublic:\n    int minDays(vector<int>& bloomDay, int m, int k) {\n        \n    }\n};",
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                    "code": "class Solution {\n    public int minDays(int[] bloomDay, int m, int k) {\n        \n    }\n}",
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                    "lang": "Python",
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                    "code": "class Solution(object):\n    def minDays(self, bloomDay, m, k):\n        \"\"\"\n        :type bloomDay: List[int]\n        :type m: int\n        :type k: int\n        :rtype: int\n        \"\"\"\n        ",
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                    "code": "class Solution:\n    def minDays(self, bloomDay: List[int], m: int, k: int) -> int:\n        ",
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                    "code": "\n\nint minDays(int* bloomDay, int bloomDaySize, int m, int k){\n\n}",
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                    "code": "public class Solution {\n    public int MinDays(int[] bloomDay, int m, int k) {\n        \n    }\n}",
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                    "lang": "JavaScript",
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                    "code": "/**\n * @param {number[]} bloomDay\n * @param {number} m\n * @param {number} k\n * @return {number}\n */\nvar minDays = function(bloomDay, m, k) {\n    \n};",
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                    "lang": "Ruby",
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                    "code": "# @param {Integer[]} bloom_day\n# @param {Integer} m\n# @param {Integer} k\n# @return {Integer}\ndef min_days(bloom_day, m, k)\n    \nend",
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                    "code": "class Solution {\n    func minDays(_ bloomDay: [Int], _ m: Int, _ k: Int) -> Int {\n        \n    }\n}",
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                    "lang": "Go",
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                    "code": "func minDays(bloomDay []int, m int, k int) int {\n    \n}",
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                    "lang": "Scala",
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                    "code": "object Solution {\n    def minDays(bloomDay: Array[Int], m: Int, k: Int): Int = {\n        \n    }\n}",
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                    "code": "class Solution {\n    fun minDays(bloomDay: IntArray, m: Int, k: Int): Int {\n        \n    }\n}",
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                    "lang": "Rust",
                    "langSlug": "rust",
                    "code": "impl Solution {\n    pub fn min_days(bloom_day: Vec<i32>, m: i32, k: i32) -> i32 {\n        \n    }\n}",
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                    "lang": "PHP",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer[] $bloomDay\n     * @param Integer $m\n     * @param Integer $k\n     * @return Integer\n     */\n    function minDays($bloomDay, $m, $k) {\n        \n    }\n}",
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                    "lang": "TypeScript",
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                    "code": "function minDays(bloomDay: number[], m: number, k: number): number {\n\n};",
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            "hints": [
                "If we can make m or more bouquets at day x, then we can still make m or more bouquets at any day y > x.",
                "We can check easily if we can make enough bouquets at day x if we can get group adjacent flowers at day x."
            ],
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