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            "questionId": "1487",
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            "title": "Cinema Seat Allocation",
            "titleSlug": "cinema-seat-allocation",
            "content": "<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/02/14/cinema_seats_1.png\" style=\"width: 400px; height: 149px;\" /></p>\n\n<p>A cinema&nbsp;has <code>n</code>&nbsp;rows of seats, numbered from 1 to <code>n</code>&nbsp;and there are ten&nbsp;seats in each row, labelled from 1&nbsp;to 10&nbsp;as shown in the figure above.</p>\n\n<p>Given the array <code>reservedSeats</code> containing the numbers of seats already reserved, for example, <code>reservedSeats[i] = [3,8]</code>&nbsp;means the seat located in row <strong>3</strong> and labelled with <b>8</b>&nbsp;is already reserved.</p>\n\n<p><em>Return the maximum number of four-person groups&nbsp;you can assign on the cinema&nbsp;seats.</em> A four-person group&nbsp;occupies four&nbsp;adjacent seats <strong>in one single row</strong>. Seats across an aisle (such as [3,3]&nbsp;and [3,4]) are not considered to be adjacent, but there is an exceptional case&nbsp;on which an aisle split&nbsp;a four-person group, in that case, the aisle split&nbsp;a four-person group in the middle,&nbsp;which means to have two people on each side.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/02/14/cinema_seats_3.png\" style=\"width: 400px; height: 96px;\" /></p>\n\n<pre>\n<strong>Input:</strong> n = 3, reservedSeats = [[1,2],[1,3],[1,8],[2,6],[3,1],[3,10]]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> The figure above shows the optimal allocation for four groups, where seats mark with blue are already reserved and contiguous seats mark with orange are for one group.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 2, reservedSeats = [[2,1],[1,8],[2,6]]\n<strong>Output:</strong> 2\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 4, reservedSeats = [[4,3],[1,4],[4,6],[1,7]]\n<strong>Output:</strong> 4\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10^9</code></li>\n\t<li><code>1 &lt;=&nbsp;reservedSeats.length &lt;= min(10*n, 10^4)</code></li>\n\t<li><code>reservedSeats[i].length == 2</code></li>\n\t<li><code>1&nbsp;&lt;=&nbsp;reservedSeats[i][0] &lt;= n</code></li>\n\t<li><code>1 &lt;=&nbsp;reservedSeats[i][1] &lt;= 10</code></li>\n\t<li>All <code>reservedSeats[i]</code> are distinct.</li>\n</ul>\n",
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                    "lang": "C++",
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                    "code": "class Solution {\npublic:\n    int maxNumberOfFamilies(int n, vector<vector<int>>& reservedSeats) {\n        \n    }\n};",
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                    "code": "class Solution {\n    public int maxNumberOfFamilies(int n, int[][] reservedSeats) {\n        \n    }\n}",
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                    "code": "class Solution(object):\n    def maxNumberOfFamilies(self, n, reservedSeats):\n        \"\"\"\n        :type n: int\n        :type reservedSeats: List[List[int]]\n        :rtype: int\n        \"\"\"\n        ",
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                    "code": "class Solution:\n    def maxNumberOfFamilies(self, n: int, reservedSeats: List[List[int]]) -> int:\n        ",
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                    "lang": "C",
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                    "code": "\n\nint maxNumberOfFamilies(int n, int** reservedSeats, int reservedSeatsSize, int* reservedSeatsColSize){\n\n}",
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                    "code": "public class Solution {\n    public int MaxNumberOfFamilies(int n, int[][] reservedSeats) {\n        \n    }\n}",
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                    "code": "/**\n * @param {number} n\n * @param {number[][]} reservedSeats\n * @return {number}\n */\nvar maxNumberOfFamilies = function(n, reservedSeats) {\n    \n};",
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                    "code": "# @param {Integer} n\n# @param {Integer[][]} reserved_seats\n# @return {Integer}\ndef max_number_of_families(n, reserved_seats)\n    \nend",
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                    "code": "class Solution {\n    func maxNumberOfFamilies(_ n: Int, _ reservedSeats: [[Int]]) -> Int {\n        \n    }\n}",
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                    "lang": "Go",
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                    "code": "func maxNumberOfFamilies(n int, reservedSeats [][]int) int {\n    \n}",
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                    "code": "object Solution {\n    def maxNumberOfFamilies(n: Int, reservedSeats: Array[Array[Int]]): Int = {\n        \n    }\n}",
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                    "code": "class Solution {\n    fun maxNumberOfFamilies(n: Int, reservedSeats: Array<IntArray>): Int {\n        \n    }\n}",
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                    "code": "impl Solution {\n    pub fn max_number_of_families(n: i32, reserved_seats: Vec<Vec<i32>>) -> i32 {\n        \n    }\n}",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer $n\n     * @param Integer[][] $reservedSeats\n     * @return Integer\n     */\n    function maxNumberOfFamilies($n, $reservedSeats) {\n        \n    }\n}",
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                    "code": "(define/contract (max-number-of-families n reservedSeats)\n  (-> exact-integer? (listof (listof exact-integer?)) exact-integer?)\n\n  )",
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                    "lang": "Erlang",
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                    "code": "-spec max_number_of_families(N :: integer(), ReservedSeats :: [[integer()]]) -> integer().\nmax_number_of_families(N, ReservedSeats) ->\n  .",
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                    "code": "defmodule Solution do\n  @spec max_number_of_families(n :: integer, reserved_seats :: [[integer]]) :: integer\n  def max_number_of_families(n, reserved_seats) do\n\n  end\nend",
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            "hints": [
                "Note you can allocate at most two families in one row.",
                "Greedily check if you can allocate seats for two families, one family or none.",
                "Process only rows that appear in the input, for other rows you can always allocate seats for two families."
            ],
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