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            "title": "Finding the Users Active Minutes",
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            "content": "<p>You are given the logs for users&#39; actions on LeetCode, and an integer <code>k</code>. The logs are represented by a 2D integer array <code>logs</code> where each <code>logs[i] = [ID<sub>i</sub>, time<sub>i</sub>]</code> indicates that the user with <code>ID<sub>i</sub></code> performed an action at the minute <code>time<sub>i</sub></code>.</p>\n\n<p><strong>Multiple users</strong> can perform actions simultaneously, and a single user can perform <strong>multiple actions</strong> in the same minute.</p>\n\n<p>The <strong>user active minutes (UAM)</strong> for a given user is defined as the <strong>number of unique minutes</strong> in which the user performed an action on LeetCode. A minute can only be counted once, even if multiple actions occur during it.</p>\n\n<p>You are to calculate a <strong>1-indexed</strong> array <code>answer</code> of size <code>k</code> such that, for each <code>j</code> (<code>1 &lt;= j &lt;= k</code>), <code>answer[j]</code> is the <strong>number of users</strong> whose <strong>UAM</strong> equals <code>j</code>.</p>\n\n<p>Return <i>the array </i><code>answer</code><i> as described above</i>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> logs = [[0,5],[1,2],[0,2],[0,5],[1,3]], k = 5\n<strong>Output:</strong> [0,2,0,0,0]\n<strong>Explanation:</strong>\nThe user with ID=0 performed actions at minutes 5, 2, and 5 again. Hence, they have a UAM of 2 (minute 5 is only counted once).\nThe user with ID=1 performed actions at minutes 2 and 3. Hence, they have a UAM of 2.\nSince both users have a UAM of 2, answer[2] is 2, and the remaining answer[j] values are 0.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> logs = [[1,1],[2,2],[2,3]], k = 4\n<strong>Output:</strong> [1,1,0,0]\n<strong>Explanation:</strong>\nThe user with ID=1 performed a single action at minute 1. Hence, they have a UAM of 1.\nThe user with ID=2 performed actions at minutes 2 and 3. Hence, they have a UAM of 2.\nThere is one user with a UAM of 1 and one with a UAM of 2.\nHence, answer[1] = 1, answer[2] = 1, and the remaining values are 0.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= logs.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= ID<sub>i</sub> &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= time<sub>i</sub> &lt;= 10<sup>5</sup></code></li>\n\t<li><code>k</code> is in the range <code>[The maximum <strong>UAM</strong> for a user, 10<sup>5</sup>]</code>.</li>\n</ul>\n",
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                    "code": "class Solution(object):\n    def findingUsersActiveMinutes(self, logs, k):\n        \"\"\"\n        :type logs: List[List[int]]\n        :type k: int\n        :rtype: List[int]\n        \"\"\"\n        ",
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                    "code": "/**\n * @param {number[][]} logs\n * @param {number} k\n * @return {number[]}\n */\nvar findingUsersActiveMinutes = function(logs, k) {\n    \n};",
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                    "code": "impl Solution {\n    pub fn finding_users_active_minutes(logs: Vec<Vec<i32>>, k: i32) -> Vec<i32> {\n        \n    }\n}",
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                "Try to find the number of different minutes when action happened for each user.",
                "For each user increase the value of the answer array index which matches the UAM for this user."
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